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Alex
2 years ago
12

Find the cost per roll if a bag of five lunch rolls is $2.50

Mathematics
2 answers:
Leviafan [203]2 years ago
7 0

\rule{300}{3}

\text{Hi!}

To find the cost per item (or in your case "rolls"), you will first have to divide the cost of the lunch rolls  (2.50)  by the amount of lunch rolls there are (5).

So in this case, it would look like

\textbf{$2.50/5}\text{$2.50 ÷ 5}\text{$2.50 / 5}\text{2.50} ÷ \text{5}

\text{=$0.50}= \text{\ 0.50}

\boxed{\$0.50{}}

\rule{300}{3}

Arturiano [62]2 years ago
3 0

Answer:

$ 0.50

Step-by-step explanation:

Cost of 5 lunch rolls = $ 2.50

Cost of 1 roll

= 2.50 / 5

= $ 0.50

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Answer:

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Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b²  = (b² + 2a²)²

2. Solve for x

\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}

\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}

5 0
3 years ago
$250, 2.85%, 3 years Simple interest
rosijanka [135]
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8 0
3 years ago
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emmainna [20.7K]

Answer:

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Step-by-step explanation:

Total hours worked by Lee = sum of all the hours worked

That’s

82 + 61 + 7 + 73 = 223 hours

Therefore, Lee worked 223 hours as manager for the local Pizza Hut

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