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3 years ago

True or false

2 answers:

7 0

False, any number to the power of zero = one

False, any number to the first power equals the number
(example 9^1 = 9, or 100^1 = 100)

True, 5^2 = 5 x 5

hope this helps

Dmitriy789 [7]3 years ago

3 0

It’s false hope it helps !

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3 years ago

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What is the GCF of 15 and 48?

miv72 [106K]

Answer:

3 is the GCF. of 15 and 48

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2 years ago

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A(n) is a point where three or more edges intersect.

Usimov [2.4K]

It is called a point of concurrency

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3 years ago

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Convert the inequalities into equations, and then use the substitution method to find four possible vertices in the form (x, y,

alina1380 [7]

Answer:

For 2x + 5y < 100, x + y < 30. Vertices : (50,0) , (0,20) , (35,0) , (0,35) , (25,0)

Step-by-step explanation:

Considering inequality equations

i) 2x + 5y < 100 ;

ii) x + y < 35

Concerting them to equality conditions

i) 2x + 5y =100.

Intercepts : If y = 0, x = 50. So, (50,0). If x = 0, y = 20. So, (0,20)

ii) x + y = 35. Intercepts :

Intercepts : If y = 0, x = 35. So, (35,0). If x = 0, y = 35 So, (0,35)

Solving them as per equality (with substitution)

From ii), x = 35 - y . Putting the value in i)

2 (35 - y) + 5y = 100 → 70 - 2y + 5y = 100 → 70 + 3y = 100

3y = 100 - 70 → 3y = 30 → y = 30 / 3 = 10

Putting y = 10 in ii) : x = 35 - 10 = 25

As per the 'less than' inequalities : the inner 'towards origin' area from both lines is in common shaded area.

Henceworth, vertices are : (50,0) , (0,20) , (35,0) , (0,35) & intersection (25,0)

8 0

3 years ago

(1 pt) Find a vector parametrization of the circle of radius 8 in the xy-plane, centered at (−3,−5), oriented counterclockwise.

creativ13 [48]

Answer:

$x(t)=8 \cos(t) -3\\\\y(t)=8 \sin(t)-5$

Step-by-step explanation:

The equation of the circle centered at (-3,-5) in the xy-plane is

$(x+3)^2+(y+5)^2=8^2$

hence in vector parametrization, we have

$x+3=8\cos(t)\\\\y+5=8\sin(t)$

and so

$x(t)=8\cos(t)-3\\\\y(t)=8\sin(t)-5$

Moreover, note that

$x(0)=8\cos(0)-3=8-3=5\\\\y(0)=8\sin(0)-5=0-5=-5$

Otherwise, we should have used a parametrization and we are done.

4 0

3 years ago