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2 years ago

Please help me!!!!!!!!

Mathematics

1 answer:

hoa [83]2 years ago

3 0

Answer:

Step-by-step explanation:

<u>Option a,c,e,f,i,j are quadratic equations. (Because its degree is 2)</u>

<u>Option b,d,g are linear equations. (Because its degree is 1)</u>

<u>Just option h is not quadratics nor linear.</u>

<u />

<h3><u>If you need to ask any questions, please let me know.</u></h3>

You might be interested in

Can someone solve this?

inn [45]

Answer:

1. 15 degrees.

2. 90 degrees.

3. 66 degrees.

Step-by-step explanation:

M and 2 appear to be 90 degrees. This is because there are parallel sides on the left and right of the kite. So, 2 is 90 degrees.

E and 75 are corresponding (I don't remember the postulate or whatnot) so 90 degrees plus 75 degrees is 165 degrees. There are 180 degrees in a triangle, so 180 minus 165 is 15. 1 Has to be 15 degrees.

3 is 66 degrees since it is corresponding with the angle on the other side of T (I, once again, do not remember the postulate).

6 0

2 years ago

Workers in an office of 40 staff were asked their favourite type of take-away.

xeze [42]

Answer:

the pie chart is not drawn to scale, its a rough sketch. so please use a protracter to scale yours more accuratly

hope it helps

7 0

2 years ago

Read 2 more answers

A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.

Reptile [31]

Answer:

a.P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}$

Step-by-step explanation:

We are given that a linear differential equation

$y''+2y=e^{3x}+x^3$

We have to find the particular solution

P.I= $\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}$

P.I= $\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}$

P.I= $\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3$

P.I= $\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0}$ (higher order terms can be neglected

P.I= $\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)$

b.Characteristics equation

$D^2+2=0$

$D=\pm\sqrt2 i$

C.F= $C_1cos \sqrt2x+C_2 sin\sqrt2 x$

G.S=C.F+P.I

G.S= $C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)$

3 0

3 years ago

As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim

AlekseyPX

Answer:

0.44

Step-by-step explanation:

Given the estimated logistic regression model on risk of having squamous cell carcinoma

-4.84 + 4.6*(SMOKER)

SMOKER = 0 (non-smoker) ; 1 (SMOKER)

What is the predicted probability of a smoker having squamous cell carcinoma?

exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))

SMOKER = 1

exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)

exp^(-0.24) / (1 + exp^(-0.24))

0.7866278 / 1.7866278

= 0.4402863

= 0.44

3 0

2 years ago

Give an example of two numbers that are both 6-digit numbers, but the greater number is determined by the hundreds place

SashulF [63]

The order of the numbers for a 6-digit number from left to right is as follows:
hundred thousands, ten thousands, thousands, hundreds, tens and then units

We want two numbers were the greater number is determined by its hundreds place, these two numbers can be:
165,827 and 165,229
The hundreds in the first is 8 while the hundreds in the second is 2. Therefore, the first number is larger.

6 0

2 years ago

Please help me!!!!!!!!​

Please help me!!!!!!!!