In y=kx , subst. -30 for x and 3 for y. Then solve the resulting equation for k:
3 = k(-30).
Dividing both sides by -30, we get:
-3/30 = -1/10 = k
The constant of proportionality is k = -1/10.
Given:
Universal set is all positive integers {1,2,3...}
Set A is the set of all positive <u>ODD</u> integers {1,3,5,7...}
The question asks us to find
, which is the <em>complement of set A</em>. The complement of a set refers to elements NOT in that set. Hence, complement of A should be all the elements NOT in A but in Universal Set, U.
It is clear from the question that set A houses all the odd positive numbers, so complement of A will have all the even positive numbers. Last choice is the correct one.
ANSWER:
"{x|x ∈ U and is an even positive integer}"
Answer:
third side = 6
using pythagoras theorem:
a² + b² = c²
Answer:
When x=10 , y= 120
When x = 1\2 , y = 6
Step-by-step explanation:
X=2/4,y=6
10 *6 = 0.5y
10*6 *2 =y
120=y
0.5 (6)= 0.5 y
Y=6
500m/2min = 250m/1min= 250m/min.
Hope this helps!