Answer:
x is in the range [-1,4]
Step-by-step explanation:
I haven't worked with absolute value inequalities in awhile, but let's take a wack at this.
We are given the following inequality:
| 2x - 3 | <= 5
This implies two possible cases:
[1] -5 <= 2x -3
Or
[2] 2x - 3 <= 5
So let's solve x for both of these cases:
[1] -5 <= 2x - 3
-2 <= 2x
-1 <= x
[2] 2x - 3 <= 5
2x <= 8
x <= 4
So from these cases, we can say the following is true:
x >= -1 and x <= 4
Thus, we can write this in the form
-1 <= x <= 4
Or in interval notation:
{ x is element of reals | -1 <= x <= 4}
Also written as
x is in the range [-1,4]
Where the closed brackets represent 1 and 4 as possible answers whereas parenthesis would imply they were not.
Cheers.
We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0
y^2-3y=0
y(y-3)=0
y1=0 -----------y2=3
Answer:

note that -11 itself is not included. the circle is empty, not filled
Thw answer is -51
Found through long division
40*52= 2080
34840 / 2080 = $16.75 an hour