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Agata [3.3K]
3 years ago
10

Given minimum and maximum data entries and the number of classes min = 75, max = 280, 10 classes. Write the first five lower cla

ss limit.
Mathematics
1 answer:
Kamila [148]3 years ago
6 0

The lower class limit is simply the least data element that can enter a class.

The first five lower class limits are: 75 , 96, 117, 138 and 159

The given parameters are:

\mathbf{Min = 75}

\mathbf{Max = 280}

\mathbf{Class = 10}

Calculate the range

\mathbf{Range = Max - Min}

\mathbf{Range = 280 - 75}

\mathbf{Range = 205}

Divide by the number of classes, to determine the class width

\mathbf{n =\frac{205}{10}}

\mathbf{n =20.5}

Approximate

\mathbf{n =21}

So, the lower limits are:

\mathbf{Lower = 75  \times 0, 75 + 21  \times 1, 75 + 21 \times 2, 75 +  \times 3, 75 +  \times 4}

\mathbf{Lower = 75 , 96, 117, 138 , 159}

Hence, the first five lower class limits are: 75 , 96, 117, 138 and 159

Read more about lower class limits at:

brainly.com/question/7949481

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schepotkina [342]

Given:

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To find:

The constant of proportionality and the equation for the proportional relationship.

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y is proportional to x.

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3 years ago
Write an expression to describe the sequence below. Use n to represent the position of a term in the sequence, where n = 1 for t
Marizza181 [45]

Answer:

a_n = -2 + n is an expression which describe the given sequence

Step-by-step explanation:

Arithmetic sequence states that a sequence where the difference between each successive pair of terms is the same.  

The general rule for the arithmetic sequence is given by;  

a_n =a_1+(n-1)d               ......[1]

where

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and n is the number of terms;

Given sequence: -1 , 0 , 1 , 2 , .....

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Since,

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3 years ago
Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
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Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

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