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Agata [3.3K]
3 years ago
10

Given minimum and maximum data entries and the number of classes min = 75, max = 280, 10 classes. Write the first five lower cla

ss limit.
Mathematics
1 answer:
Kamila [148]3 years ago
6 0

The lower class limit is simply the least data element that can enter a class.

The first five lower class limits are: 75 , 96, 117, 138 and 159

The given parameters are:

\mathbf{Min = 75}

\mathbf{Max = 280}

\mathbf{Class = 10}

Calculate the range

\mathbf{Range = Max - Min}

\mathbf{Range = 280 - 75}

\mathbf{Range = 205}

Divide by the number of classes, to determine the class width

\mathbf{n =\frac{205}{10}}

\mathbf{n =20.5}

Approximate

\mathbf{n =21}

So, the lower limits are:

\mathbf{Lower = 75  \times 0, 75 + 21  \times 1, 75 + 21 \times 2, 75 +  \times 3, 75 +  \times 4}

\mathbf{Lower = 75 , 96, 117, 138 , 159}

Hence, the first five lower class limits are: 75 , 96, 117, 138 and 159

Read more about lower class limits at:

brainly.com/question/7949481

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One satellite is scheduled to be launched from Cape Canaveral in Florida, and another launching is scheduled for Vandenberg Air
Lisa [10]

Answer:

P(A) = 0.45

P(B) = 0.32

Step-by-step explanation:

Given

P(A) > P(B)

P(A\ u\ B) = 0.626

P(A\ n\ B) = 0.144

Required

Find P(A) and P(B)

We have that:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

and

P(A\ n\ B) = P(A) * P(B) --- (2)

The equations become:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

0.626 = P(A) + P(B) - 0.144

Collect like terms

P(A) + P(B) = 0.626 + 0.144

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Make P(A) the subject

P(A) = 0.770 - P(B)

P(A\ n\ B) = P(A) * P(B) --- (2)

0.144 = P(A) * P(B)

P(A) * P(B) = 0.144

Substitute: P(A) = 0.770 - P(B)

[0.770 - P(B)] * P(B) = 0.144

Open bracket

0.770P(B) - P(B)^2 = 0.144

Represent P(B) with x

0.770x - x^2 = 0.144

Rewrite as:

x^2 - 0.770x + 0.144 = 0

Expand

x^2 - 0.45x - 0.32x + 0.144 = 0

Factorize:

x[x - 0.45] - 0.32[x - 0.45]= 0

Factor out x - 0.45

[x - 0.32][x - 0.45]= 0

Split

x - 0.32= 0 \ or\ x - 0.45= 0

Solve for x

x = 0.32\ or\ x = 0.45

Recall that:

P(B) = x

So, we have:

P(B) = 0.32 \ or \ P(B) = 0.45

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P(A) = 0.45 \ or\ P(A) =0.32

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