Step-by-step explanation:
7 √(1/3) - 2 1/3 √(1/3) +3√147
→7(1/√3) - (7/3)(1/√3) +3√(3×7×7)
→ (7/√3) - (7/3√3) +3×7√3
→ (7/√3) - (7/3√3) + 21√3
On Rationalising the denominators then
→ [ 7√3/(√3×√3)]-[7√3/(3×√3×√3) +21√3
The Rationalising factor of√3 =√3
→ (7√3/3)-[7√3/(3×3)]+21√3
→ (7√3/3)-(7√3/9)+21√3
LCM of 3 and 9 = 9
→ [(3×7√3)-(7√3)+(9×21√3)]/9
→ (21√3-7√3+189√3)/9
→[(21-7+189)√3]/9
→ [(210-7)√3]/9
→ 203√3/9 Ans.
Hope this helps.
