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SashulF [63]
3 years ago
12

An amusement park recently increased the cost of a family season pass. The original price was $150. The new price is $183. What

was the percent of increase or markup?
Mathematics
1 answer:
viva [34]3 years ago
6 0

Answer:

1.22%

Step-by-step explanation:

150 x 1.22 = 183

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What is the area of rectangle with the length of 5/8 in a width of 4/9 foot​
VladimirAG [237]

Answer:

he was a member of the first paragraph of the first paragraph of the first paragraph of the first paragraph of the first paragraph of the first paragraph of the first

8 0
3 years ago
Solve for 2.<br> 5x - 5<br> 1<br> r - 2<br> 3
Alborosie

Answer:

x= 13 /14

Step-by-step explanation:

Let's solve your equation step-by-step.

5x−5

x−2

=

1

3

Step 1: Cross-multiply.

5x−5

x−2

=

1

3

(5x−5)*(3)=1*(x−2)

15x−15=x−2

Step 2: Subtract x from both sides.

15x−15−x=x−2−x

14x−15=−2

Step 3: Add 15 to both sides.

14x−15+15=−2+15

14x=13

Step 4: Divide both sides by 14.

14x

14

=

13

14

x=

13

14

5 0
3 years ago
Please help with this equation!! ASAP <br><br> x + 10 &lt; 0.1 or y + 10 &gt; 9.9
Andru [333]
I need more information!
8 0
3 years ago
A prospective mother and a prospective father are hemophiliacs. (Enter your answers as fractions.)
Katena32 [7]

So remember that Hemophilia is <u>a recessive, x linked trait.</u>

For a woman to have hemophilia, she must have the trait linked to both x chromosomes. For a man to have hemophilia, he must have the trait linked to his singular x chromosome.

For this, I will be making a Punnett Square to determine the Possibilities:

\left[\begin{array}{cccc}&&X_h&Y\\&&-&-\\X_h&|&X_hX_h&X_hY\\X_h&|&X_hX_h&X_hY\end{array}\right]

<h3>A.</h3>

Since there is a 1/2 chance for their offspring to be a boy, and of that 1/2 both would be hemophiliacs, <u>there is a 1/2 chance for the child to be a hemophiliac male.</u>

<h3>B.</h3>

As previously mentioned, for a woman to have hemophilia, they would need to have that trait attached to both x chromosomes. Since there is a 1/2 chance for their offspring to be a girl, and of that 1/2 both would be hemophiliacs (since they both carry the trait on both chromosomes), <u>there is a 1/2 chance that they will have a hemophiliac female.</u>

<h3>C.</h3>

<u>So a carrier is someone who carries a recessive trait, but it isn't displayed due to the dominant trait masking it. With x-linked traits, only women can be carriers since they carry more than one x chromosome.</u> What this asks is the probability of an offspring having the trait attached to only 1 of the x chromosomes. Looking at the girls, since both carry the traits on both x chromosomes, <u>there is 0 chance of a carrier.</u>

<h3>D.</h3>

So symptom free is as it seems, without the hemophilia trait. Looking at the table, since all the offspring contain the hemophilia trait, <u>there is 0 chance that any of their offspring will go symptom free.</u>

7 0
3 years ago
Order of Operation
pochemuha
Answer:
21
Step by step explanation:
So, what we know is that we have 3 field goals, each worth 3 points, and 2 touchdowns, each worth 6 points. So we can do: 3 * 3 + 2 * 6. To break this down we first must do 3 * 3. This gets us an answer of 9, we then must do 2 * 6. Which gives us an answer of 12. Now that we have multiplied the 2, we may add, 9 + 12 = 21. Meaning our answer is 21. I hope this helped you out! If you have any questions leave a comment
5 0
3 years ago
Read 2 more answers
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