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Anni [7]
2 years ago
9

What is 5/6 of 78kg?

Mathematics
2 answers:
Tpy6a [65]2 years ago
6 0

Answer:

65kg

Step-by-step explanation:

5/6*78kg=65kg

<em>hope it helps</em>

<em>brainliest please</em>

Dmitriy789 [7]2 years ago
3 0
65 kg i think or 143 pounds
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Choose the correct simplification of the expression 3b/a-2
Goshia [24]
To solving with their equation and expression to step by step.

3b/a-2

= -2a+3b/a


4 0
3 years ago
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Need help ASAP! i will give brainliest :)
emmasim [6.3K]

Answer:

96 cm^2

Step-by-step explanation:

Total Surface Area of a square pyramid:

A = L + B = a2 + a√(a2 + 4h2))

A = a(a + √(a2 + 4h2))

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3 years ago
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Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
Uncle John has 30 lemon trees and 36 lime trees to plant on his grove. He would like to plant the trees in rows where each row h
7nadin3 [17]

Answer:

6

Step-by-step explanation:

this question is basically asking you to find the HCF of 30 and 36

step 1 : draw prime factor tree diagrams and write the numbers out as the product if their prime factors

step 2: multiply the prime factors they have in common

30 = 2 x 3 x 5

36 = 2 x 2 x 3 x 3

HCF = 2 x 3 = 6

8 0
2 years ago
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21x+28=14 and 9x+12y=6
Westkost [7]
<span>21x+28=14
x= -2/3 or -0.666666666

</span><span>9x+12y=6
x=2/3 or .666666666
y=0</span>
7 0
3 years ago
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