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anastassius [24]

3 years ago

13

Simplify (5x2 + 3x + 4) + (5x2 + 5x - 1).

1 answer:

marishachu [46]3 years ago

5 0

23+8X is the answer to this problem

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Pls help I need the answer

alexandr402 [8]

Answer:

The first choice.

8 0

2 years ago

Read 2 more answers

Choose one of the factors of 6x^3 + 6

ivanzaharov [21]

Answer: First option is correct.

Step-by-step explanation:

Since we have given that

$6x^3+6$

Now, by factorising , we get

$6x^3+6\\=6(x^3+1)$

Now, we use the formula i.e.

$a^3+b^3=(a+b)(a^2-ab+b^2)$

By using this, we get ,

$6(x^3+1)\\=6(x+1)(x^2-x+1)$

So,

$(x+1) \text{ is the factor of }6x^3+6.$

6 0

3 years ago

Read 2 more answers

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0

3 years ago

What is 31 in tens and ones

My name is Ann [436]

3 is in the tens and 1 is in the ones. To explain more easily... 30+1 is 31.<span />

5 0

3 years ago

Rectangle A has a length of 2x + 6 and a width of 3x. Rectangle B has a length of x + 2 and an area of 12 square units greater t

Maurinko [17]

So here is how you solve for the answer.
Firstly, you solve for the Area of Rectangle A.
The formula for Area is Length x width.
So A = (2x + 6)(3x) and the result is: 6x^2 + 18x
Now, let y be the width of rectangle B.
<span>(x+2) (y) = 6x^2 + 18x + 12
(x+2) y = 6(x+1)(x+2)
y = 6(x+1)
</span>So the final answer would be width is 6x + 6. The answer is the third option. Hope this answer helps.

7 0

4 years ago