Solve the Linear Quadratic system of equations y=x^(2)+2x-9 y=-2x+3
1 answer:
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Answer:
(x, y) = (-6, 15) and (2, -1)
Step-by-step explanation:
You can start by subtracting the second equation from the first.
(y) -(y) = (x^2 +2x -9) -(-2x +3)
0 = x^2 +4x -12 . . . . . . collect terms
0 = (x +6)(x -2) . . . . . . . factor
Solutions for x are -6 and +2. These values make the factors zero.
The corresponding solutions for y are ...
y = -2(-6) +3 = 15
y = -2(2) +3 = -1
Solutions to the system of equations are ...
(x, y) = (-6, 15) and (2, -1)
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Answer:
Step-by-step explanation:
The given polynomial has zeros at:
x=−3, x=−1, and x=1.
This means that:
x+3, x+1, and x-1 are all factors of this polynomial.
The factored form of this polynomial is :
We expand the last two factors using difference of two squares.
This is the standard form because it is now in decreasing powers of x.