The total number of coins is 9. Therefore
p+n+d = 9 (1)
There are two fewer nickels than dimes. Therefore
n = d - 2 (2)
From (1) and (2), obtain
p+(d-2)+d = 9
p + 2d = 11
p = 11 - 2d (3)
Total value:
0.01p + 0.05n + 0.10d = 0.53 (4)
Substitute (2) and (3) into (4).
0.01(11-2d) + 0.05(d-2) + 0.10d = 0.53
0.11 - 0.02d + 0.05d - 0.10 + 0.10d = 0.53
0.03d + 0.01 = 0.53
0.13d = 0.52
d = 4
p = 11 - 2d = 11 - 8 = 3
Answer: 3 pennies
Answer:
Step-by-step explanation:
<-- Given
<-- Multiply by the conjugate of the denominator as a factor of 1
<-- Use the Distributive Property and FOIL
<-- Rewrite 
as 
<-- Rewrite in 
form
Siiiii, Se conoce como número primo a cada número natural que sólo puede dividirse por 1 y por sí mismo. ... Como el único número primo par es 2, suele citarse como número primo impar a cualquier número primo que sea más grande que éste.
Answer:
y = 3x + 7.
Step-by-step explanation:
The slope = 6/2 = 3
y-intercept = 7.
Let the first page = x
The second page would be x + 1
Add them together to equal 347
X + x + 1 = 347
Combine like terms:
2x + 1 = 347
Subtract 1 from both sides
2x = 346
Divide both sides by 2:
X = 173
The smaller page number is 173
The larger page number is 174
