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2 years ago

PLEASE HELP! I GIVE BRAINLIEST AND POINTS plz no links LOOK AT THE PIC BELOW

Mathematics

1 answer:

Svetach [21]2 years ago

7 0

Hi the answer is the result of (a3)-2

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May someone pls help me

ratelena [41]

Answer:

kim

Step-by-step explanation:

1/4 will be a hole and a fraction so you are able to do it in your head

6 0

2 years ago

Which is equivalent to [3_/125]x

Murrr4er [49]

Answer:

[5]x

Step-by-step explanation:

7 0

2 years ago

For f(x) = 3x^2 + 2x - 1, identify the rule for g(x) = f(x + 1) - 6 and it's graph.

PilotLPTM [1.2K]

2x2 + x −#6 _____________

x2 − 1

∙ x

2 + 2x + 1

x 2 − 4

Rewrite as multiplication.

(2x − 3)(x + 2) __

(x + 1)(x − 1) ∙ (x + 1)(x + 1) __ (x + 2)(x − 2) Factor the numerator and denominator.

(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Multiply numerators and denominators.

(2x − 3)(x + 2)(x + 1)(x + 1) ___ (x + 1)(x − 1)(x + 2)(x − 2) Cancel common factors to simplify.

(2x − 3)(x + 1) __ (x − 1)(x − 2)

4 0

2 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

2 years ago

Joe's bill at grocery store came to $6.08 he paid with a $10 bill and a dime how much change do you get Joe's bill at the grocer

Levart [38]

Answer:

$4.02

Step-by-step explanation:

$10.10 - $6.08 = $4.02

7 0

3 years ago

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