Answer:
1, 2, and 5
Step-by-step explanation:
The given scale for the map means that a distance of 1 cm between two locations on the map corresponds to a real distance between them of 600,000 cm = 6 km.
So, if the distance between two places in reality is 87 km, on the map this would be represented by a distance of 14.5 cm, since
87 = 84 + 3
87 = 6 • 14 + 6 • (1/2)
87 = 6 • (14 + 1/2)
For this problem, the confidence interval is the one we are looking
for. Since the confidence level is not given, we assume that it is 95%.
The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n
Where:
<span>
</span>
α= 5%
α/2
= 2.5%
t
0.025, 19 = 2.093 (check t table)
n
= 20
df
= n – 1 = 20 – 1 = 19
So plugging in our values:
8.41 ± 2.093 * 0.77 √ 1 + 1/20
= 8.41 ± 2.093 * 0.77 (1.0247)
= 8.41 ± 2.093 * 0.789019
= 8.41 ± 1.65141676
<span>= 6.7586 < x < 10.0614</span>
Answer:
Step-by-step explanation: 3root5x^2 + 25x - 10root5 = 0
3xroot5 + 25x - 10root5 = 0 [ root x^2 = x]
28x root5 = 10 root5 [ -10root5 turns to 10 root5 when transferred to RHS]
28x root 5/root5 =10
28x=10
x = 10/28
x = 0.35
Hope it helped u,
pls mark as the brainliest
^v^
So...
Each bottle of apple juice has 2 litters of juice, so, if he bought y bottles of apple juice, we will have to multiply.
12 liters of apple juice3 liters of orange juice
