ip a standard sheet of paper measures 8 1/2 by 11 inches. find the area of one such sheet of paper in
1 answer:
The area of the standard sheet of paper is 93 1/2 square inches.
The standard sheet of paper is a rectangle and to find its area, multiply the length by the width.
The area of the rectangle is the region enclosed by the perimeter of the rectangle and is equal to product of length and width.
If the standard sheet of paper has a length of 11 inches and a width of 8 1/2 inches, then:
A = l * w
A = 11 x 8 1/2
A = 93 1/2 square inches
Hence, the area of the standard sheet of paper is 93 1/2 square inches.
To learn more about area of rectangle: brainly.com/question/25292087
#SPJ4
You might be interested in
Answer:
<em>The building is 61.5 m tall</em>
Step-by-step explanation:
The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:
h = height of the building
a, b = internal angles of each triangle
x = base of each triangle
The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:
a = 90° - 37° = 53°
b = 90° - 42° = 48°
Now we apply the tangent ratio on both triangles separately:
From the last equation:
Substituting into the first equation:
Operating on the right side:
Rearranging:
Solving for h:
Calculating:
h = 61.5 m
The building is 61.5 m tall
