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umka2103 [35]
2 years ago
12

Two mechanics worked on a car. The first mechanic charged $55 per hour, and the second mechanic charged $60 per hour. The mechan

ics worked for a combined total of 20 hours, and together they charged a total of $1125. How long did each mechanic work?
​
Mathematics
1 answer:
Nady [450]2 years ago
8 0

Answer:

15 and 5 hours.

Step-by-step explanation:

Call x the time taken by the first chap, and y the second.

\left \{ {{x+y = 20 \atop {55x+60y=1125}} \right.

Let's divide by 5 and play with the LHS of the first equation a bit:

11x+ 11y +y = 225\\11(x+y)+y= 225 we know how much x+y is ( first equation!) let's solve.

11(20) +y = 225 \rightarrow y=5 At this point it's easy to check that x=15

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This is an incomplete question, the correct question is given below.

Find the missing number of each unit rate \frac{15}{5}=\frac{?}{1} and \frac{24}{6}=\frac{?}{1}

Answer : The missing number of each unit rate of \frac{15}{5}=\frac{?}{1} and \frac{24}{6}=\frac{?}{1} are, 3 and 4 respectively.

Step-by-step explanation :

As we know that a unit rate is a rate in which 1 is present in denominator.

Or we can say that,

A unit rate is also called a single unit rate that means it will compare 1 unit of some quantity to a different units of a different quantity.

As we are given that that unit rates:

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Now we have to determine the missing number of each unit rates.

So, we can write the given expression as:

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Thus, the missing number is, 3

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When are dividing 24 by 6, we get:

\frac{24}{6}=\frac{4}{1}

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<em>Hope that helps!</em>

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