Answer:
i think its c
Step-by-step explanation:
The feeders in battling machine are represented in proportions and fractions.
- The equation that represents the problem is:
- The feeder can hold <em>30 baseballs</em>, when full
The given parameters are:
<em />
<em> ------ 1/6 full</em>
<em />
<em> --- baseballs added</em>
<em />
<em> ---- 2/3 full</em>
<em />
So, the equation that represents the problem is:
So, we have:
The number of baseballs it can hold is calculated as follows:
Multiply through by 6
Collect like terms
Divide through by 3
Hence, the feeder can hold 30 baseballs, when full
Read more about proportions and fractions at:
brainly.com/question/20337104
The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width.
Area = Length x Height
Area = (20 in) x (14 in)
Area = 280 in²
We are given that the area is only equal to 192 in². We subtract this value from the computed area.
Difference = 280 in² - 192 in²
difference = 88 in²
This area is equal to the area of the hollow space inside the frame. That is equal to,
height = 20 in - 2x
length = 14 in - 2x
The area,
88 = (20 - 2x)(14 - 2x)
Simplify the right hand side of the equation.
88 = 280 - 68x + 4x²
Divide the equation by 4,
22 = 70 - 17x + x²
Transposing,
x² - 17x - 48 = 0
The factors of the equation is 58.2.
Thus, the thickenss is equal to 58.2 in
x = -52 4/17
the full answer in attachments
Answer:
slope = -4/5 y-intercept = 1
Step-by-step explanation:
y = -4/5+1
