Answer:
B. vertical asymptote: x = 1
horizontal asymptote: y = 0
Step-by-step explanation:
1) Vertical asymptotes of a function are determined by what input of x makes the denominator equal 0. So, let's set the denominator,
, equal to 0 and solve for x:
![x^3-1= 0\\x^3 = 1\\\sqrt[3]{x^3} = \sqrt[3]{1} \\x = 1](https://tex.z-dn.net/?f=x%5E3-1%3D%200%5C%5Cx%5E3%20%3D%201%5C%5C%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B1%7D%20%5C%5Cx%20%3D%201)
Thus, the vertical asymptote is x = 1.
2) If the degree of the polynomial in the denominator is greater than the one on the top, the horizontal asymptote is automatically y = 0. Thus, the horizontal asymptote is y = 0.
1. 700
2. 3,900
These are the answers I found :)
Answer:
i think its 2
Step-by-step explanation:
Answer:
BAC=29=BOC/2
Step-by-step explanation:
Answer:
b) (-6, 0)
Step-by-step explanation:
The quickest method to use is to put "0" in for <em>y</em><em>,</em><em> </em>then figure out which term for <em>x</em> would make the equation authentic, or genuine.