Question

How do i solve ∑(n→∞)〖4.594 ln(n)- 0.8129〗

Answer 1

For every $n \geq 2$, we have

$4.594\log(n)-0.8129>1$

So, negletting the first term, each term of the sum is greater than 1, which implies

$\displaystyle \sum_{n=2}^\infty 4.594\log(n)-0.8129> \sum_{n=1}^\infty 1 =\infty$

Which means that the series diverges.

Answer 2

Answer:

The series diverges.

Step-by-step explanation:

Apply the limit test: The Limit of 4.594 ln(n)- 0.8129 as n ---> ∞ is  ∞  (not equal to 0) , so the series diverges.