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jarptica [38.1K]

3 years ago

12

Please help ! posted picture of problem

2 answers:

inna [77]3 years ago

4 0

For a linear function: The graph is a straight line
For a non-linear function: The graph is not a straight line

The given graph is not a straight line and is rather a curve with several turning points i.e several ups and downs. Hence the graph belongs to a Non-Linear Function.

A relation is non-function when it passes through same x value more than once. Since this cannot be observed in the given graph, the graph belongs to a function.

Therefore, the correct answer to this question is "Non-Linear Function"

poizon [28]3 years ago

3 0

B? i believe it is ?????

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<h2>Answer:</h2>

$\boxed{\overline{MN}=37.96}$

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find $\overline{MN}$ . Since:

$\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm$

and $\overline{MN}$ is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

$\overline{RN}=\overline{QN}$

By Pythagorean theorem, for triangle NQP:

$\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}$

Applying Pythagorean theorem again, but for triangle MQN:

$\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}$

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