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Free_Kalibri [48]
2 years ago
6

If a- b= 2 and ab= 15 then a3-b3?a) 30 b) 98 c) 20 d) 60full explanation please​

Mathematics
2 answers:
krek1111 [17]2 years ago
7 0

Answer:

C) 20

Step-by-step explanation:

ab=15

5*3 = 15

which is a and which is b

a - b = +2

5 - 3 = + 2

------------------

a = 5 and

b = 3

------------------

a3-b3 = 53 - 33 = 20

seraphim [82]2 years ago
6 0

Answer:

The answer is 98

Step-by-step explanation:

A = 5

B = 3

a_b = 2

a × b = 5 × 3 = 15

A3 _ b3 =(5) bower 3 _ (3) power 3 = 98

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B is not geometric because it is an arithmetic sequence. 

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\frac{1}{6}\\

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To find the probability, divide the number of desired outcomes by the total:

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At leslie's school the ratio of boys and girls is 11 to 12 at marks school the ratio of boys girls is 41 to 48 if both schools h
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Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

Step-by-step explanation:

Here are the options:

A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.

B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

At leslie's school the ratio of boys and girls is 11 to 12. This implies that the fraction of boys in the school to total students will be:

= 11/(11 + 12) = 11/23 = 0.4783

At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:

= 41 / (41 + 48) = 41/85= 0.4824

Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

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