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BigorU [14]
3 years ago
9

Wich graph best represents a function with range -4 < y < 3

Mathematics
1 answer:
anygoal [31]3 years ago
8 0

Answer:

Witch craft or Which graph?!!

Step-by-step explanation:

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PLEASE HELP THIS IS DUE BY TOMORROW
Bezzdna [24]

Answer:b

Step-by-step explanation:

4 0
3 years ago
Find the volume of the figure shown below.
Alex777 [14]
10 cm would stay as a 10 cm
14cm would round down to a 10
3 0
2 years ago
Using the image, find the slope of the line. Reduce all fractions and enter using a forward slash (i.e. "/"). If the slope is un
dusya [7]

9514 1404 393

Answer:

  0

Step-by-step explanation:

The slope of a horizontal line is zero (0). For any finite "run", the "rise" is zero.

  slope = rise/run = 0/run = 0

8 0
3 years ago
What are the solutions to the equation
frosja888 [35]

Answer:

C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

Step-by-step explanation:

You have the quadratic function 2x^2-x+1=0 to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions ax^2+bx+c=0 with a\neq 0 the Bhaskara's Formula is:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}

It usually has two solutions.

Then we have  2x^2-x+1=0  where a=2, b=-1 and c=1. Applying the formula:

x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}

Observation: \sqrt{-1}=i

x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i

And,

x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i

Then the correct answer is option C.

x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i and x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i

3 0
3 years ago
Use substitution to solve for x in the system of equations.
jolli1 [7]
Equation 1) 10x + 2y = 30
Equation 2) 4x + y = 4

Multiply all of equation 2 by 2.

2)  2(4x + y = 4)

2)  8x + 2y = 8
1)  10x + 2y = 30

Subtract equations from each other.

-2x = -22

Divide both sides by -2.

x = -22/-2

x = 11

B) x = 11

~Hope I helped!~


6 0
3 years ago
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