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BigorU [14]
3 years ago
9

Wich graph best represents a function with range -4 < y < 3

Mathematics
1 answer:
anygoal [31]3 years ago
8 0

Answer:

Witch craft or Which graph?!!

Step-by-step explanation:

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Omar, Hala and Lujain got paid a total of $240 for cleaning neighborhood cars. They split the money in the ratio of 5: 9: 10. Ho
Levart [38]

Answer:

Total amount Omar earn = $120

Step-by-step explanation:

Given:

Total amount Omar, Hala and Lujain got paid = $240

Ratio of money Omar, Hala and Lujain got paid = 5:9:10

Find:

Total amount Omar earn

Computation:

Total amount Omar earn = [Total amount Omar, Hala and Lujain got paid][Omar'ratio / Total ratio]

Total amount Omar earn = [240][5 / (5+9+10)]

Total amount Omar earn = [240][5 / (24)]

Total amount Omar earn = [24][5]

Total amount Omar earn = $120

5 0
3 years ago
tim brought a car 25000 and it depreciation $350 per year. What is the value of the car after 6 years?
blondinia [14]

Answer:

22900

Step-by-step explanation:

multiply 350 by 6 and get 2100

subtract 2100 from 25k and get 22900

6 0
4 years ago
Read 2 more answers
The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75 at
satela [25.4K]
The total cost is the dependant variable and the number of tickets along with flat out price is the independent variable.

The equation would be y = 1.25x + ?

You would insert 25 for x which equals 31.25 and insert 43.75 for y.

43.75 = 31.25 + ? Then subtract 31.25 from both sides of the equation and you would get....

12.5 = ?

That is your flat rate to get in to the fair 




7 0
4 years ago
Solve the inequality <br><br> 4b
Mnenie [13.5K]
Could you maybe provide us with a better explantion or picture?
4 0
3 years ago
PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!​
KonstantinChe [14]

Answer:

b.  \displaystyle \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle H(x) = \sqrt[3]{F(x)}<em />

<em />

<u>Step 2: Differentiate</u>

  1. Rewrite function [Exponential Rule - Root Rewrite]:                                      \displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}
  2. Chain Rule:                                                                                                        \displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]
  3. Basic Power Rule:                                                                                             \displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)
  4. Simplify:                                                                                                             \displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}
  5. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}
  2. Substitute in function values:                                                                          \displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}
  3. Exponents:                                                                                                        \displaystyle H'(5) = \frac{6}{3(4)}
  4. Multiply:                                                                                                             \displaystyle H'(5) = \frac{6}{12}
  5. Simplify:                                                                                                             \displaystyle H'(5) = \frac{1}{2}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0
3 years ago
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