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olga55 [171]
3 years ago
10

Change this time to 12-hour clock what is anwer

Mathematics
1 answer:
Anna [14]3 years ago
3 0

Answer:

2.Military Time 0327 is: 03:27 AM using 12-hour clock notation, 03:27 using 24-hour clock notation.

3.Military Time 0048 is: 12:48 AM using 12-hour clock notation, 00:48 using 24-hour clock notation.

5.Military Time 0600 is: 06:00 AM using 12-hour clock notation, 06:00 using 24-hour clock notation.

6.Converting 24-Hour Time to 12-Hour Time. Add 12 to the first hour of the day and include “AM.” In 24-hour time, midnight is signified as 00:00. So, for midnight hour, add 12 and the signifier “AM” to convert to 12-hour time.

1.05:29 PM using 12-hour clock notation, 17:29 using 24-hour clock notation.

4.11:58 PM using 12-hour clock notation, 23:58 using 24-hour clock notation.

7.09:44 PM using 12-hour clock notation, 21:44 using 24-hour clock notation.

8.10:48 PM using 12-hour clock notation, 22:48 using 24-hour clock notation.

9.11:55 PM using 12-hour clock notation, 23:55 using 24-hour clock notation

(I've put the question numbers according to how you've asked it in the question)

Hope you've understood ☺️

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What is the range for this set of data?<br> 7, 15, 12<br> O 3<br> O 5<br> О ООО<br> 12
IRINA_888 [86]

Answer: 15

Step-by-step explanation:

max - min 15-0 = 15

5 0
3 years ago
Help me with this problem please right away​
svlad2 [7]

Answer:

6\frac{1}{2} = A

Step-by-step explanation:

The first step is to use the Distance Formula to figure out the lengths of the two legs:

\sqrt{[-x_1 + x_2]^{2} + [-y_1 + y_2]^{2}} = D

R(1, 1) and P(−1, −2) ↷

\sqrt{[1 + 1]^{2} + [2 + 1]^{2}} = \sqrt{2^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13}\\ \\ \sqrt{13} = RP

Q(2, −4) and P(−1, −2) ↷

\sqrt{[1 + 2]^{2} + [2 - 4]^{2}} = \sqrt{[-2]^{2} + 3^{2}} = \sqrt{4 + 9} = \sqrt{13} \\ \\ \sqrt{13} = QP

* So, by my calculations, we have an isosceles <em>right triangle</em>, and according to the <em>45°-45°-90° triangle theorem</em>, we automatically know that the hypotenuse, <em>RQ</em>, is \sqrt{26}:

30°-60°-90° triangle theorem

2x, x, x√3

↑ ↑ ↑

h leg leg

y

p

o

t

e

n

u

s

e

45°-45°-90° triangle theorem

x√2, x, x

↑ ↑ ↑

h legs

y

p

o

t

e

n

u

s

e

So now, we have to find the area of the triangle by taking half of either height or base, then multiplying that by the height or base, but since this is an isosceles <em>right</em><em> </em><em>triangle</em><em>,</em><em> </em>it does not matter:

[\frac{h}{2}][b] = A \: \:OR\: \: [\frac{b}{2}][h] = A \: \:OR \: \: \frac{hb}{2} = A

[\frac{\sqrt{13}}{2}][\sqrt{13}] = \frac{13}{2} = 6\frac{1}{2} \\ \\ 6\frac{1}{2} = A

I am joyous to assist you anytime.

8 0
3 years ago
That is my question ​
schepotkina [342]
The Answer to this is 10 seconds
7 0
4 years ago
If u get paid 12.00 dollar 40 hours how much money will i have at the end of the month
Lelechka [254]
If she works 40 hours getting paid $12 an hour she will get $480
3 0
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Solve for y in terms of x.<br><br>3x^2 + 2x + 4 = y​
Sav [38]

Answer:

y=-1+squareroot 47l /6, -1- squaroot 47l/6

Step-by-step explanation:

3x^2 +2x+4−x=0

3x^2 +x+4=0

y=-1+squareroot 47l /6, -1- squaroot 47l/6

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