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3 years ago

One of these graphs is of a cubic function. Which one is it?

Mathematics

2 answers:

Firlakuza [10]3 years ago

6 0

Answer:

Step-by-step explanation:

It is because it is in form f(x) =ax³+cx+d.

Where the coefficients are a, b, c, and d.

The variable 'x' takes real values, and a ≠ 0 in other words.

Schach [20]3 years ago

5 0

Answer:

Step-by-step explanation:

D is the correct answer. It is a cubic function

You might be interested in

Is the formula s=(n-2)180

Phantasy [73]

Answer:

Number of sides of the polygon

Step-by-step explanation:

The formula $S=(n-2)180$ is the sum of the measures of interior angles. So that's what S stands for. The only other variable remaining is n which is the number of sides of the polygon.

There's nothing I can do to help you understand this, you just have to memorize it.

5 0

3 years ago

How far apart in feet are Marcus and Joel. Please round your answer to the nearest tenth of a foot

Pavel [41]

Answer:

The distance between Marcus and Joel is approximately 127.3 feet.

Step-by-step explanation:

The distances between Jean to Joel, Jean to Marcus and Marcus to Joel form a right triangle where the distance from Marcus to Joel is the hypothenuse. We can measure the distance from Jean to Marcus and Jean to Joel by using the grid provided, since they're along the same axis. This is shown below:

d(Jean, Marcus) = Jean(x) - Marcus(x) = 100 - 10 = 90 feet

d(Jean, Joel) = Jean(y) - Joel(y) = 90 - 0 = 90 feet

We can apply the pythagora's theorem to find the distance between Marcus and Joel.

d(Marcus,Joel)² = d(Jean,Marcus)² + d(Jean,Joel)²

d(Marcus,Joel)² = (90)² + (90)²

d(Marcus,Joel)² = 2*(90)²

d(Marcus, Joel) = sqrt(2*(90)²) = 90*sqrt(2) = 127.279 feet

The distance between Marcus and Joel is approximately 127.3 feet.

8 0

4 years ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

<u>Answer:</u>

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

<u>Solution: </u>

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$