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VashaNatasha [74]
3 years ago
10

One of these graphs is of a cubic function. Which one is it? ​

Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0

Answer:

D

Step-by-step explanation:

It is because it is in form f(x) =ax³+cx+d.

Where the coefficients are a, b, c, and d.

The variable 'x' takes real values, and a ≠ 0 in other words.

Schach [20]3 years ago
5 0

Answer:

D

Step-by-step explanation:

D is the correct answer. It is a cubic function

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Graph the solution set to the inequality.​
Alex73 [517]

Answer:

2nd graph

Step-by-step explanation:

- s / 2 ≥ 9

-s ≥ 9 x 2

S ≤ 18

7 0
3 years ago
A toy store’s percentage of markup is 25%. A modeltrain costs the store $120. Find themarkup.
Alex Ar [27]
The correct answer is letter B
5 0
3 years ago
Maurice's teacher asked him to compare the mean and median of the data distribution explain and correct Maurice's error in compa
Dmitry_Shevchenko [17]

The first part where he mentions "The distribution is skewed right" is correct. The tail on the right hand side is pulled longer than it should be, or longer compared to the left tail. "Right skew" or "skewed right" is the same as "positively skewed". They all mean the same thing.

The portion where Maurice says "This implies that the mean is less than the median" is incorrect. This is where his error is located. The reason for the error is because it should be "The mean is greater than the median" when we have right-skewed data like this.

Here's one example to see why this is the case. Consider the distribution {1,2,3,4,5}. We can see that the median is 3 since it's directly in the center. The mean is also 3 since we add up all the values and divide by 5. Symmetric data has mean = median. Now, we'll replace the '5' with something much larger to get a large outlier. Let's say we have the set {1,2,3,4,55}. The median is still 3. The outlier doesn't pull on the median. However, the mean has changed and it is (1+2+3+4+55)/5 = 65/5 = 13. The mean went from 3 to 13. Therefore, mean > median here. The mean is affected by outliers. Think of it like the outlier is pulling on the mean in a sort of magnetic way. This outlier makes the mean larger than it should be. If the outlier is extreme enough, then it sometimes makes sense to consider the trimmed mean as opposed to the regular arithmetic mean. The trimmed mean is the mean of the main cluster of values ignoring the outlier(s).

-----------------------

To recap:

If we have right skewed data, then mean > median

As you can probably guess, if we had left-skewed data, then mean < median. In symmetric data, mean = median.

4 0
3 years ago
Plato Question!!!!
Katyanochek1 [597]

Answer:

(2, 120° )

Step-by-step explanation:

To convert from rectangular to polar form, that is

(x, y) → (r, Θ ), use

r = \sqrt{x^2+y^2}

Θ = tan^{-1}( \frac{y}{x})

here (x, y ) = (- 1, \sqrt{3})

r = \sqrt{(-1)^2+(\sqrt{3} } )^2

  = \sqrt{1+3} = \sqrt{4} = 2

Θ = tan^{-1}(\sqrt{3}) = 60° ← related acute angle

Note (- 1, \sqrt{3}) is in the second quadrant so Θ must be in the second quadrant.

Θ = 180° - 60° = 120°

(- 1, \sqrt{3}) → (2, 120°)

7 0
3 years ago
Read 2 more answers
If one inch represents 3 units, what dimensions would you use to draw a rectangular field that is 20 units by 14 units?​
mezya [45]

Answer:

Step-by-step explanation:

If 1 inch = 3 units,

Therefore 1 unit = ⅓ inches, so to answer your question we have to

Multiply it by 20, to have :

20 units = 20× ⅓ = 20÷3

20 units = 6.66

Therefore we can use the same principle in that of 14 units.

14 units = (14 × ⅓) inches

14 units = 4.66 inches

PLEASE GIVE BRAINLIEST.

5 0
3 years ago
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