So it would be x12 to the 2nd power, kinda hard to explain but i really hope this helped
The given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.
What do you mean by absolute maximum and minimum ?
A function has largest possible value at an absolute maximum point, whereas its lowest possible value can be found at an absolute minimum point.
It is given that function is f(x) = |x + 3|.
We know that to check if function is absolute minimum or absolute maximum by putting the value of modulus either equal to zero or equal to or less than zero and simplify.
So , if we put |x + 3| = 0 , then :
± x + 3 = 0
±x = -3
So , we can have two values of x which are either -3 or 3.
The value 3 will be absolute maximum and -3 will be absolute minimum.
Therefore , the given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.
Learn more about absolute maximum and minimum here :
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2(4x - 7) -1 = 11
8x - 14 -1 = 11
8x - 15 = 11
+ 15 + 15
8x = 26
/8 /8
x = 3. 25 ------> Rounded: 3.30
Answer:
I’m pretty sure that’s - 11/3 .
Step-by-step explanation:
Answer:
f(1)=13
f(-9)=88
f(0)=0
f(-15)=20
The above mentioned are false statements
Step-by-step explanation:
f(1)=13 : false because "13" is out of range -40≤f(x)≤-10
f(-9)=88 : false because "88" is out of range -40≤f(x)≤-10
f(0)=0 : false because "0" is out of range -40≤f(x)≤-10
f(-15)=-20 : false because "-15" is out of domain -10≤x≤20
