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2 years ago

Write as a fraction 3÷151

Mathematics

2 answers:

stepan [7]2 years ago

6 0

3/151, cannot be simplified further

stepan [7]2 years ago

3 0

Answer:

3/151

Step-by-step explanation:

That's the answer

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What are to shapes that have to parallel sides

faltersainse [42]

The parallelogram, rectangle, and square all have two pairs of parallel sides

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3 years ago

Read 2 more answers

A magician has a collection of 52 cards, with 26 red and 26 black cards. Four of these cards are classified as 'special', and tw

Brums [2.3K]

Answer:

option B (28/52)

Step-by-step explanation:

from probability

P(A∪B)=P(A)+P(B)-P(A∩B)

where

P(A∪B) = probability that event A or B happen

P(A∩B) = probability that event A and B happen simultaneously

P(A) = probability that event A happen

P(B) = probability that event B happen

the probability that the card is special or red

P( special or red)= P(special) + P(red) - P( special and red)

since

P(special)= 4/52

P(red) = 26/52

P( special and red) = 2/52

therefore

P( special or red)= 4/52 + 26/52 - 2/52 = 28/52

P( special or red)= 28/52

(option B)

6 0

3 years ago

A rectangle has an area of 18cm^2. The lengths of the sides are whole numbers. How long can each of the sides be? Give all the e

babymother [125]

Answer:

Area of rectangle = l x b

18 = l x b

Factors of 18 =

1 x 18 = 18

2 x 9 = 18

3 x 6 = 18

So each of the sides can be either 1cm and 18 cm, 2cm and 9cm and 3cm and 6cm.

6 0

3 years ago

A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea

Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let x be the width and y the length of the rectangular field.

Let C the total cost of the rectangular field.

The side made of heavy duty material of length of x costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are x, y, y. Thus

$C=4x+4y+4y+16x\\C=20x+8y$

We know that the total area of rectangular field should be 2250 square yards,

$x\cdot y=2250$

We can say that $y=\frac{2250}{x}$

Substituting into the total cost of the rectangular field, we get

$C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}$

We have to figure out where the function is increasing and decreasing. Differentiating,

$\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}$

Next, we find the critical points of the derivative

$20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30$

Because the length is always positive the only point we take is $x=30$ . We thus test the intervals $(0, 30)$ and $(30, \infty)$

$C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0$

we see that total cost function is decreasing on $(0, 30)$ and increasing on $(30, \infty)$ . Therefore, the minimum is attained at $x=30$ , so the minimal cost is

$C(30)=20(30)+\frac{18000}{30}\\C(30)=1200$

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0

3 years ago

Please help due tomorrow

vlabodo [156]

Answer:

10 hrs

Step-by-step explanation:

just divide 24 km by 8 hrs to get 3km per hour then

divide 30 by 3 to get 10 hrs

3 0

3 years ago

Write as a fraction 3÷151​

Write as a fraction 3÷151