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3 years ago

0.000456 in scientific notation (Please answer fast this is on my final math exam!)

Mathematics

2 answers:

N76 [4]3 years ago

3 0

Answer:

0.000456 in scientific notation

= 4.56 × 10-4

Step-by-step explanation:

Can I have brainliest?

dalvyx [7]3 years ago

3 0

0.000456 in scientific notation is 4.56 × 10-4

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What is 3.315 rounded to the nearest hundredth

Maksim231197 [3]

the hundreth place is .0(0)0 (first zero being tenths, second being hundreths, third being thousanths and so on)

Because the place to the right is a 5, we round up (4 or less is down)

3.32 would be rounded from 3.315

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3 years ago

Whoever helps me with this question gets points

ohaa [14]

Answer:

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2 years ago

In right triangle <ABC,<br>M<A = 42°. Find m<B.

wlad13 [49]

Answer:

m<B is 48°

Step-by-step explanation:

m<C is already 90°

m<A is 42°

42+90+x=180

132+x=180

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3 years ago

Barbara has 9 stuffed animals Trish has three times as many stuffed animals as Barbara how many stuffed animals does Trish have

Rainbow [258]

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27 is the answer

4 0

3 years ago

Suppose that prices of a certain model of new homes are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule to

konstantin123 [22]

Answer:

C. 47.5%

Step-by-step explanation:

The summary of the given statistics include:

mean =150000

standard deviation: 1200

The objective is to use tributed with a mean of $150,000. Use the 68-95-99.7 rule to find the percentage of buyers who paid: between $150,000 and $152,400

The z score formula can be use to calculate the percentage of the buyer who paid.

$z = \dfrac{X - \mu}{\sigma}$

For the sample mean x = 150000

$z = \dfrac{150000 - 150000}{1200}$

$z = \dfrac{0}{1200}$

z = 0

For the sample mean x = 152400

$z = \dfrac{152400 - 150000}{1200}$

$z = \dfrac{2400 }{1200}$

z = 2

From the standard normal distribution tables

P(150000 < X < 152400) = P(0 < z < 2 )

P(150000 < X < 152400) =P(z<2) -P(z<0)

P(150000 < X < 152400) =0.9772 -0.5

P(150000 < X < 152400) = 0.4772

P(150000 < X < 152400) = 47.7% which is close to 47.5% therefore option C is correct

3 0

3 years ago