Adding 1/4 and 5/8 using the giant one to create a common denominator

Consider the first order differential equation

AURORKA [14]

Answer:

For y(-7) =6.4

The largest interval is between

$-\infty \to -5$

For y(-2.5) = -0.5.

The largest interval is between

$-5 \to 5$

For y(0) = 0

The largest interval is between

$-5 \to 5$

For y(4.5) = -2.1.

The largest interval is between

$-5 \to 5$

For y(14)= 1.7.

The largest interval is between

$9 \to \infty$

Step-by-step explanation:

From m the question we are told that

The first order differential equation is $\frac{y' - t}{ t^2 -25} = \frac{e^t}{t-9}$

Now the first step is to obtain the domain of the differential equation

Now to do that let consider the denominators

Now generally

$t^2 - 25 \ne 0$ side calculation

=> $t\ne \pm5$ $t^2 - 25 = 0$

$t = \pm 5$

Also $t-9\ne 0$ $t -9 = 0$

=> $t\ne 9$ $t= 9$

This means that this first order differential equation is discontinuous at

$t = -5 , \ \ t = 5 \ \ t = 9$

$This \ is \ illustrated \ below \ \\ ------------------\\\. \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ |\\. \ -5 \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ 9$

So

For y(-7) =6.4

The largest interval is between

$-\infty \to -5$

For y(-2.5) = -0.5.

The largest interval is between

$-5 \to 5$

For y(0) = 0

The largest interval is between

$-5 \to 5$

For y(4.5) = -2.1.

The largest interval is between

$-5 \to 5$

For y(14)= 1.7.

The largest interval is between

$9 \to \infty$

4 0

3 years ago

A quadrilateral has the following vertices on a coordinate plane:

dolphi86 [110]

<h3>Answer: 4</h3>

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Explanation:

We'll only focus on points J and K.

J = (3, -6)

K = (-1, -6)

Because these two points have the same y coordinate (which is -6), this means we can ignore those values and subtract the x coordinates

3 minus (-1) = 3 - (-1) = 3 + 1 = 4

Or we could plot points J and K on the same xy grid system, and count out the number of spaces between J and K. You should count out 4 spaces.

This means segment JK is 4 units long.

8 0

3 years ago

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Find the percent of increase from 1.5 inches to 6 inches

Maslowich

Answer:

25%

Step-by-step explanation:

6 0

3 years ago

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What is the sum of negative nine and negative two?

mash [69]

The answer to this sum is negative seven

5 0

3 years ago

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What must be the value of x so that lines a and b are parallel lines cut by transversal f?

ExtremeBDS [4]

we know that

if the lines a and b are parallel lines cut by transversal f

then

$(6x-36)=96$ --------> by alternate exterior angles

solve for x

$(6x-36)=96\\ 6x=96+36\\6x=132\\x=(132/6)\\x=22\ degrees$

therefore

<u>the answer is</u>

the value of x is $22\ degrees$

5 0

3 years ago

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