A=(1,2) and b=(2, - 1) . Find 4a - 3b
1st carry out the scalar multiplication 4a and -3b
4a =[4(1) , 4(2) ] = (4 , 8)
-3b = [-3(2) . -3(-1)] = (-6 , +3)
4a - 3b = [(4-6) , (8+3)] = (-2 , 11)
Answer:
bvghb vbub b
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Answer:
1.) Some
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Natural numbers do not contain negative numbers, but they do contain whole numbers like 1, 2, 3. So your answer would be some.
Answer: 21!!
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