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Vlada [557]
2 years ago
11

If the set of values represent points on a line, what is the value of a?

Mathematics
1 answer:
goldenfox [79]2 years ago
6 0

Answer:

a = 7

Step-by-step explanation:

Equation of line : y = mx + b

m = slope

Plug in coordinates:  

Slope = Change in y/Change in X

Slope = 13-4/5-2 = 9/3 = 3

Plug in coordinates:

y - intercept = b

13 = 5(3) + b

13 = 15 + b

b = -2

Equation: y = 3x - 2

Input 3 for x

y = 3x - 2

y = 9 - 2

y = 7

-Chetan K

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Write the formula for the parabola that has x- intercepts (1.3,0) and (-1.3,0), and y- intercept (0,169).
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Answer: (8, 45)?

Step-by-step explanation:

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3 years ago
the vertex form of the equation of a parabola is y=(x-5)2+16. what is the standard form of the equation
Reika [66]

Answer:

y = x² - 10x + 41

Step-by-step explanation:

The standard form of a quadratic is ax² + bx + c : a ≠ 0

Given

y = (x - 5)² + 16 ← expand (x - 5)²

 = x² - 10x + 25 + 16

 = x² - 10x + 41 ← in standard form

6 0
4 years ago
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Traeq pays 35.34 for 3.1 pounds of salmon. What is the price per pound of salmon
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$11.40 because you just divide 35.34 by 3.1
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3 years ago
The teacher has 15 gold prize ribbons, 22 blue ribbons, and 5e red ribbons. There are 12 boys and 18 girls in the class. If the
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Answer:

3

Step-by-step explanation:

Given

15 gold ribbons

22 blue ribbons

53 red ribbons

Total of 53 + 22 + 15 = 90 ribbons

Total number of students = 12 boys + 18 girls = 30 students.

If evenly divided, each student will have 90/30 = 3 ribbons

The expression to solve would basically be the amalgamation of what we did above:

(53 + 22 + 15)/(12+18)

4 0
3 years ago
One study reports that 34​% of newly hired MBAs are confronted with unethical business practices during their first year of empl
MaRussiya [10]

Answer:

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

\hat p=0.28 estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

p_o=0.34 is the value that we want to test

\alpha=0.05 represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:  

Null hypothesis:p=0.34  

Alternative hypothesis:p \neq 0.34  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

The p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.  

5 0
4 years ago
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