The <u>congruency theorem</u> gives you an opportunity to prove that <u>two triangles</u> are <u>congruent</u>.
Consider triangles WUT and VTU. In these triangles:
- WU≅VT (given);
- ∠T≅∠U, m∠T=m∠U=90° (from the diagram);
- side TU is common.
Note that triangles WUT and VTU are right triangles, because m∠T=m∠U=90°. Side TU is common leg and sides WU and VT are hypotenuses.
HL theorem states: if the hypotenuse (WU) and one leg (TU) of a right triangle (ΔWUT) are congruent to the hypotenuse (VT) and one leg (TU) of another right triangle (ΔVTU), then the triangles are congruent.
Answer: correct choice is B
Answer:
I need the values of either X or Y to solve this. I can solve for what X is though.
Step-by-step explanation:
A: X = -12
B: X =78
C: X = 12.13
I hope this helps you, but since both X and Y are unknown variables, you can't solve it, only simplify (which it already is.)
Solve for x:
4 (6 x + 1) - 3 (4 x + 3) = 43
-3 (4 x + 3) = -12 x - 9:
-12 x - 9 + 4 (6 x + 1) = 43
4 (6 x + 1) = 24 x + 4:
24 x + 4 - 12 x - 9 = 43
Grouping like terms, 24 x - 12 x - 9 + 4 = (24 x - 12 x) + (4 - 9):
(24 x - 12 x) + (4 - 9) = 43
24 x - 12 x = 12 x:
12 x + (4 - 9) = 43
4 - 9 = -5:
12 x + -5 = 43
Add 5 to both sides:
12 x + (5 - 5) = 5 + 43
5 - 5 = 0:
12 x = 43 + 5
43 + 5 = 48:
12 x = 48
Divide both sides of 12 x = 48 by 12:
(12 x)/12 = 48/12
12/12 = 1:
x = 48/12
The gcd of 48 and 12 is 12, so 48/12 = (12×4)/(12×1) = 12/12×4 = 4:
Answer: x = 4
Answer:
|x-4| +|y-5|=0
Step-by-step explanation:
There are many equations that will graph as the point (x, y) = (4, 5). One of them is ...
|x-4| +|y-5| = 0
Answer:
The correct option is (1).
Step-by-step explanation:
The given system of equation is,
..... (1)
.... (2)
The solution of the system of equation is the point where both line intersect each other.
Solve the equation by method of elimination.
Multiply equation 1 by 3.
... (3)
Add equation (2) and (3).
Put this value in equation 1.
Therefore, the lines intersect each other at (0.25,3.75). So, the first option is correct.
