Let the hamburgers be x and cheese burgers be y.
x + y = 24
3x + 3.5 y = 79
x = 24 - y.
Substituting the value of x,
3( 24 - y) + 3.5 y = 79
72- 3y + 3.5 y = 79
72 + 0.5 y = 79
0.5y = 79 - 72 = 7
1/2 y = 7
thus, y = 7 * 2 = 14
Substituting the value for x,
x + y = 24
x + 14 = 24
x = 24-14 = 10
Thus, x = 10.
Thus, she sold 10 hamburgers and 14 cheeseburgers
Answer:
A. 14x14x28
B. The maximum volume is 5488 cuibic inches
Step-by-step explanation:
The problem states that the box has square ends, so you can express volume with:
Using the restriction stated in the problem to get another equation you can substitute in the one above:
Substituting <em>y</em> whit this equation gives:
Now find the limit of <em>x</em>:
Find the length:
You can now calculate the maximum volume:
Answer:
(e) csc x − cot x − ln(1 + cos x) + C
(c) 0
Step-by-step explanation:
(e) ∫ (1 + sin x) / (1 + cos x) dx
Split the integral.
∫ 1 / (1 + cos x) dx + ∫ sin x / (1 + cos x) dx
Multiply top and bottom of first integral by the conjugate, 1 − cos x.
∫ (1 − cos x) / (1 − cos²x) dx + ∫ sin x / (1 + cos x) dx
Pythagorean identity.
∫ (1 − cos x) / (sin²x) dx + ∫ sin x / (1 + cos x) dx
Divide.
∫ (csc²x − cot x csc x) dx + ∫ sin x / (1 + cos x) dx
Integrate.
csc x − cot x − ln(1 + cos x) + C
(c) ∫₋₇⁷ erf(x) dx
= ∫₋₇⁰ erf(x) dx + ∫₀⁷ erf(x) dx
The error function is odd (erf(-x) = -erf(x)), so:
= -∫₀⁷ erf(x) dx + ∫₀⁷ erf(x) dx
= 0
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