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aleksley [76]
3 years ago
10

HELP PLEASE!!!!!!

Mathematics
1 answer:
Furkat [3]3 years ago
3 0
The problems of physics that are given here can be solved using Ohms laws. As per the Ohms law, we can write
Resistance = Current/Voltage.
Now coming to the questions that are given.
1. In this question,
Current = 15 amperes
Voltage = 5 volts
Then
Resistance = 5/15
                   = 1/3
                   = 0.33 ohms
So the resistance of the tube will be 0.33 ohms
2. Given information's are noted below
Current = 2 amperes
Voltage = 120 volts
Resistance = 120/2
                   = 60 ohms
 So 60 ohms of resistance is present in the bulb.
3. Given information's
Current = 250 watt
Voltage = 240 volts
Resistance = 250/240
                   = 25/24
                   = 1.04 ohms.
The radio will draw 1.04 ohms.
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2 3/4÷2/5 will mark brainleyst
olga55 [171]

Answer:

6 7/8

Step-by-step explanation:

Result in decimals: 6.875

In pic

(Hope this helps can I pls have brainlist (crown) ☺️)

6 0
3 years ago
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Tehara has read 115 pages of a 305 page book she reads 10 pages each day how many days will it take to finish
scZoUnD [109]

Answer: 19 days

Step-by-step explanation:

305-115=190

190 divided by 10= 19

7 0
3 years ago
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Will give brainliest! Pls help!
olga2289 [7]

A straight line equals 180 degrees, so the 3 angles in the picture need to equal 180.

X + 90 + 25 = 180

x +115 = 180

Subtract 115 from both sides:

x = 65

6 0
3 years ago
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Determine
Luden [163]

Answer:

\mu_{x} = 64, \sigma_{x} = 12.83

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu_{x} = \mu and standard deviation \sigma_{x} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 64, \sigma = 77, n = 36

So

\mu_{x} = 64, \sigma_{x} = \frac{77}{\sqrt{36}} = 12.83

7 0
4 years ago
y = x2 − 6x + 8 2y + x = 4 The pair of points representing the solution set of this system of equations is
algol [13]
2y + x = 4
x = -2y + 4

y = x^2 - 6x + 8
y = (-2y + 4)^2 - 6(-2y + 4) + 8
y = (-2y + 4)(-2y + 4) + 12y - 24 + 8
y = 4y^2 - 8y - 8y + 16 + 12y - 24 + 8
y = 4y^2 - 4y 
4y^2 - 4y - y = 0
4y^2 - 5y = 0
y(4y - 5) = 0
 
y = 0                x = -2y + 4
                        x = -2(0) + 4
                        x = 4

4y - 5 = 0          x = -2y + 4
4y = 5               x = -2(5/4) + 4
y = 5/4              x = -10/4 + 4
                         x = -10/4 + 16/4
                         x = 6/4 which reduces to 3/2

so u have 2 sets of points that will work....

(4,0) and (3/2,5/4) <===
6 0
4 years ago
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