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3 years ago

Please help i give 15 points for the answer

Mathematics

2 answers:

Hoochie [10]3 years ago

8 0

3 1/2 x 3/5= 7/2 x 3/5= 21/10 = 2 1/10

Paraphin [41]3 years ago

5 0

Answer:

2 and 9/10

Step-by-step explanation:

3 1/2- 3/5=2 9/10

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Which of the following is a polynomial? A. 15X4 B. 4X2 +9x+12 C. 3- 2x D. 6x2 +2/X

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3 years ago

Ellen’s rectangular garden is 6 feet wide and 16 feet long. One bag of mulch will cover 9 square feet. How many bags of mulch sh

ivann1987 [24]

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3 0

3 years ago

Read 2 more answers

Find the perimeter of this shape

Margaret [11]

The answer is 257.08m. Explanation: you know that one side of the square in the middle is 50m. This is the same as the diameter of one of the half circles on each side. The perimeter of a circle is the formula C=2(pi)r, where r is the radius. Dividing 50 by two will get you the size of the radius, then just plug it into the equation to find the perimeter of both rounded sides (a full circle). The two circular sides equal 157.08m, so then you just need to add the flat sides, which are both 50m since they’re congruent. 157.08m + 50m + 50m = 257.08m, so the perimeter of the shape is 257.08m.

4 0

3 years ago

Hey uh guys i need help pls thanks

vivado [14]

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7 0

3 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

3 years ago