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2 years ago

Please help i give 15 points for the answer

Mathematics

2 answers:

Hoochie [10]2 years ago

8 0

3 1/2 x 3/5= 7/2 x 3/5= 21/10 = 2 1/10

Paraphin [41]2 years ago

5 0

Answer:

2 and 9/10

Step-by-step explanation:

3 1/2- 3/5=2 9/10

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Expand the binomial (2x^2+y^2)^4

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2 years ago

deposited $175 each month the balance of the savings account in 5 years will be $12,100.how much of the final balance will come

Ugo [173]

Answer:

$1,600

Step-by-step explanation:

To find out how much of the final balance will come from the interest earned, you have to determine the total value of the deposits made and subtract this from the balance the account will have after 5 years.

amount deposited each month: $175

months: 12*5= 60

Total amount deposited: $175*60= $10,500

Interests: $12,100-$10,500= $1,600

According to this, the amount of the final balance that will come from the interest earned is $1,600.

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2 years ago

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2 years ago

What is the solution to the equation -(5-(a+1))=9-(5-(2a-3))

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2 years ago

Read 2 more answers

Hello, may I please have some help on these 4 questions? Thanks very much! {Also, if you could answer them quick, that would be

wlad13 [49]

1.

Parallelogram with base a = 20 in. and height h = 16 in.
Triangle with base a = 20 in. and height b = 8 in.

so:

$A = A_P+A_T=a\cdot h+\frac{1}{2}\cdot a\cdot b=20\cdot16+\frac{1}{2}\cdot20\cdot8=320+80=\\\\=\boxed{400\text{ in}^2}$

2.

Trapezoid with base b₁ = 14 cm, base b₂ = 4 cm and height h = 10 cm
Triangle with base b₁ = 14 cm and height x = 18 cm - 10 cm = 8 cm

so:

$A=A_T+A_\Delta=\frac{1}{2}\cdot(b_1+b_2)\cdot h+\frac{1}{2}\cdot b_1\cdot x=\\\\=
\frac{1}{2}\cdot(14+4)\cdot 10+\frac{1}{2}\cdot 14\cdot8=\frac{1}{2}\cdot18\cdot 10+\frac{1}{2}\cdot 14\cdot8=90+56=\\\\=\boxed{146\text{ cm}^2}$

3.

We have three rectangles:

$A=A_1+A_2+A_3=1\cdot 4+6\cdot5+18\cdot6=4+30+108=\boxed{142\text{ ft}^2}$

4.

Area of a circle:

$A_\circ=\pi\cdot r^2=3.14\cdot5^2=3.14\cdot25=78.5 \text{ cm}^2$

Area of a rectangle:

$A_R=8\cdot 6=48\text{ cm}^2$

Area of the shaded region:

$A=A_\circ-A_R=78.5-48=\boxed{30.5\text{ cm}^2}$

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2 years ago