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Marta_Voda [28]
2 years ago
15

You and your classmate went to get lunch and your total bill (before taxes) was $48.50. You liked the food and want to leave a t

ip of $20%. What is the tip?
Mathematics
1 answer:
Taya2010 [7]2 years ago
7 0

Answer:

9 dollars 70 cents

Step-by-step explanation:

20% of 48.50

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I WILL MAKE WHOEVER ANSWERS THIS CORRECTLY THE BRAINLIEST :D Rei is barricading a door to stop a horde of zombies. She stacks bo
ivann1987 [24]

Answer:

See below.

Step-by-step explanation:

Well first, we need to find the weight of the table. We know that 8 boxes weighs a total of 240kg (since each box weights 30kg). Thus, we can conclude that the table weighs 70kg by doing 310-240=70.

Now, we can write our function. Let x equal the amount of boxes.

The table is a set weight, so that would be our constant.

Thus, we will have:

f(x)=30x+70

30x represents the weight each box of book adds to the total. One box equals 30kg, 2 boxes equal 60kg, etc.

The 70 represents the unchanging weight of the table.

In terms of W(x), it will be:

W(x)=30x+70

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Answer:

3

Step-by-step explanation:

3x18>=3=3

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What do we call this triangle if we are looking at it's sides
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Scalene I think. Sorry it's been forever but and equilateral triangles sides are all, well, equal and an Isosceles triangle has only 2 sides the same length.
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3 years ago
A candy manufacturer claims that the average weight of their individually wrapped candy is 3 grams. Sixty-four candy pieces were
Anon25 [30]

Answer:

t=\frac{2.8-3}{\frac{0.5}{\sqrt{64}}}=-3.2    

p_v =P(t_{(63)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly lower than 3 grams at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=2.8 represent the sample mean

s=0.5 represent the sample standard deviation for the sample  

n=64 sample size  

\mu_o =3 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is lower than 3 grams, the system of hypothesis would be:  

Null hypothesis:\mu \geq 3  

Alternative hypothesis:\mu < 3  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.8-3}{\frac{0.5}{\sqrt{64}}}=-3.2    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=64-1=63  

Since is a one sided test the p value would be:  

p_v =P(t_{(63)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is significantly lower than 3 grams at 5% of signficance.  

8 0
3 years ago
We wish to estimate what percent of adult residents in a certain county are parents. Out of 500 adult residents sampled, 175 had
shepuryov [24]

Answer:

The 99% confidence interval  is  0.3003  < I  <  0.3997

Step-by-step explanation:

From the question we are told that

     The sample size is  n =  500

      The the number that are parents  x =  175

The  proportion of parents is  mathematically represented as

       \r p  =  \frac{x}{n}

substituting values

      \r  p  =  \frac{175}{500}

     \r  p  = 0.35

The  level of confidence is given as 99%  which implies that the level of significance is  

       \alpha  = 100 - 99

       \alpha =1%

      \alpha  = 0.01

The critical value for this level of significance is obtained from the table of critical value as

          t_{x, \alpha } =  t_{175, 0.05}  =  2.33

Generally the margin of error is mathematically evaluated as

       M  =\frac{ t_{175, 0.01 } *  \sqrt{\r p (1-\r p)} }{\sqrt{n} }

substituting values

     M  =\frac{ 2.33 *  \sqrt{\r 0.35 (1-0.35)} }{\sqrt{500} }

     M  = 0.0497

Generally the 99% confidence interval is mathematically represented as

        I  = \r p \pm  M

    \r  p -M  < I  <  \r p + M

substituting values

    0.35 -0.0497  < I  <   0.35 + 0.0497

    0.3003  < I  <  0.3997

5 0
3 years ago
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