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exis [7]
2 years ago
11

Please help ASAP ASAP asap

Mathematics
1 answer:
RoseWind [281]2 years ago
4 0
The answer is 7 R 4! hoped this helps!
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Simplify the expression. (3.14×107)×(1.3×10−3)÷0.2<br> Scientific notation PLS!
marusya05 [52]

3.14 \times 107 = 335.98
(335.98) \times (1.3 \times 10 - 3) \div 0.2
1.3 \times 10 = 13 - 3 = 10
(335.98) \times (10) \div 0.2
335.98 \times 10 = 3359.8
3359.8  \div 0.2 = 16799
1.6799 \times  {10}^{4}


5 0
3 years ago
Richard is $15 overdrawn on his checking account. He writes a check for $7. What is the balance in his checking account now?​
Annette [7]
Since he’s already at -15, if he writes a check for 7 then he’s subtracting more from his account.
So, -15-7=-22
5 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
3 years ago
What is (3.1 times 10 Superscript 5 Baseline) (2.2 times 10 Superscript 7 Baseline) in scientific notation? 5.5 times 10 Supersc
aev [14]

Answer:

(B) 6.82 times 10 Superscript 12

Step-by-step explanation:

I just took the quiz

8 0
3 years ago
Read 2 more answers
216,016 divided by 368
kifflom [539]

Answer:

587

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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