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creativ13 [48]
2 years ago
8

Find the slope of the graph of x^3 = ln(xy) at the point (1, e).

Mathematics
1 answer:
kkurt [141]2 years ago
6 0

Answer:

e^x^3 = xy : e^x^3 = xy

Step-by-step explanation:

=)

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What is the final answer?
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<h3>Answer:  42</h3>

Explanation:

We have y = -0.9x^2 + 76x - 250 which is in the form y = ax^2+bx+c

where,

  • a = -0.9
  • b = 76
  • c = -250

The vertex (h,k) is when the profit is maxed out.

h = -b/(2a)

h = -76/(2(-0.9))

h = 42.222 approximately

Let's plug in x values around x = 42

Try x = 41

y = -0.9x^2 + 76x - 250

y = -0.9(41)^2 + 76(41) - 250

y = 1353.10

Now try x = 42

y = -0.9x^2 + 76x - 250

y = -0.9(42)^2 + 76(42) - 250

y = 1354.4

Now try x = 43

y = -0.9x^2 + 76x - 250

y = -0.9(43)^2 + 76(43) - 250

y = 1353.9

We see that the largest profit happens when x = 42.

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Answer: indistinct, alike equivelent

Step-by-step explanation:

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Step-by-step explanation:

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