P = 12 + 6 + 8,5 = 18 + 8,5 = 26,5 mm
A = 12 × 4 / 2 = 48 / 2 = 24 mm²
Answer:
(a)
(b)5,832 Mosquitoes
(c)5 days
Step-by-step explanation:
(a)Given an original amount
at t=0. The population of the colony with a growth rate
, where k is a constant is given as:

(b)If
and the population after 1 day, N(1)=1800
Then, from our model:
N(1)=1800

Therefore, our model is:

In 3 days time

The population of mosquitoes in 3 days time will be approximately 5832.
(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.
From our model

In approximately 5 days, the population of mosquitoes will be 20,000.
A is true. Thus D is also true. The result of the synthetic division shows C is true.
The appropriate choices are ...
A. (x - 2) is a factor of 3x² - 11x + 10
C. (3x² - 11x + 10) ÷ (x - 2) = (3x - 5)
D. The number 2 is a root of F(x) = 3x² - 11x + 10