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Shtirlitz [24]
3 years ago
11

Tori ran 4/5 Mile in 1/5 hour. write an equation for the distance in miles Y that she ran in X hours if she ran at a constant ra

te​
Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

Answer:

y=4x

Step-by-step explanation:

Let

y ----> the distance in miles

x ----> the time in hours

using proportion

\frac{y}{x}=\frac{(4/5)}{(1/5)}

Simplify

\frac{y}{x}=\frac{4}{1}

y=4x

This is a linear direct variation

The unit rate or speed is the slope of the linear equation

The unit rate is 4 miles/hour

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Find the 12th term of an AP of the form 7, 12, 17, 22
Nostrana [21]

Answer:

27

Step-by-step explanation:

The rule will be

Ni=(i-1)*5+2

  • i=1 → N=(1–1)*5+2=0*5+2=0+2=2
  • i=2 → N=(2–1)*5+2=1*5+2=5+2=7
  • i=3 → N=(3–1)*5+2=2*5+2=10+2=12
  • i=4 → N=(4–1)*5+2=3*5+2=15+2=17
  • i=5 → N=(5–1)*5+2=4*5+2=20+2=22
  • i=6 → N=(6–1)*5+2=5*5+2=25+2=27

________________

Learn more about arithmetic sequences:

  • brainly.com/question/6561461
  • brainly.com/question/503167

#SPJ2

6 0
2 years ago
SOS HURRY
Burka [1]

First, by using the distance formula for just one side, we can find the length of all sides (a square has 4 equal sides.) Then, we can apply the area of a square formula, which is a^2.

Distance formula:

\sqrt{(x.2 - x.1)^{2} + (y.2 - y.1)^{2}}

√((-2 + 5)^2 + (-8 + 4)^2)

√((3)^2 + (4)^2)

√9 + 16

√25

5

The side lengths of the square are each equal to 5, and by applying the formula for area, we can find the area of the square.

5^2 = 25

<h3>The area is 25.</h3>
3 0
3 years ago
There are 10 fishes 2 drown 1 runs away and 5 died how many fishes are left?
dezoksy [38]
There are still 10 fish but only 5 are alive because fish don't drown
3 0
3 years ago
Read 2 more answers
Write 3/4 as a decimal​
ahrayia [7]

Answer:

0.75

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Given the linear programming problem, use the method of corners to determine where the minimum occurs and give the minimum value
algol [13]

Answer:

Minimum value of function C=x+10y is 63 occurs at point (3,6).

Step-by-step explanation:

To minimize :

                                   C=x+10y

Subject to constraints:

                                   x\leq 3---(1)\\y\leq 9---(2)\\x+y\geq 9----(3)\\x\geq 0\\y\geq 0

Eq (1) is in blue in figure attached and region satisfying (1) is on left of blue line

Eq (2) is in green in figure attached and region satisfying (2) is below the green line

Considering x+y\geq 9, corresponding coordinates point to draw line are (0,9) and (9,0).

Eq (3) makes line in orange in figure attached and region satisfying (3) is above the orange line

Feasible region is in triangle ABC with common points A(0,9), B(3,9) and C(3,6)

Now calculate the value of function to be minimized at each of these points.

                                    C=x+10y

at A(0,9)

                                     C=0+10(9)\\C=90

at B(3,9)

                                     C=3+10(9)\\C=93

at C(3,6)

                                     C=3+10(6)\\C=63

Minimum value of function C=x+10y is 63 occurs at point C (3,6).

3 0
3 years ago
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