Step-by-step explanation:

I hope it makes sense
:)
9. 31 + 5 = 36
10. 16 - 4 = 12
12. 9
13. 44 + 34 = 78
14. 101 - 1 = 100
15. -539 ???
16. 15 ??
17. |-435| = 435
Im pretty sure that it would be 600%. If it was 600% that would be 600 over 100 which would be 6
The missing justification in the proof is
<span>B) Substitution property of equality
The expression for sin</span>² x and cos² x is substituted to the other side of the equation. Since sin x = a/c, then sin² x = a²/c². Similarly, since cos x = b/c, then cos² x = b²/c². Adding to two results to the third statement.
The question is an illustration of related rates.
The rate of change between you and the ball is 0.01 rad per second
I added an attachment to illustrate the given parameters.
The representations on the attachment are:

---- the rate

First, we calculate the vertical distance (y) using tangent ratio

Substitute 100 for x


Differentiate both sides with respect to time (t)

Substitute values for the rates and 

This gives


Divide both sides by 2


Hence, the rate of change between you and the ball is 0.01 rad per second
Read more about related rates at:
brainly.com/question/16981791