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Liula [17]
3 years ago
6

The length of a rectangle is five centimeters more than its width, w. If the perimeter of the rectangle is 26 centimeters, what

is the area of the rectangle, in square centimeters?
A.104
B.676
C.36
D.26
Mathematics
1 answer:
dem82 [27]3 years ago
7 0
L is 5 more than W
L=5+W
P=2(L+W)
P=26
26=2(L+W)
L=5+W
sub
26=2(5+W+W)
divide both sides by 2
13=5+W+W
13=5+2W
minus 5 both sides
8=2W
divide 2 both sides
4=W

L=5+W
L=5+4
L=9

L=9 cm
W=4 cm

area=LW
area=9*4
are=36 cm^2

C is answer
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9514 1404 393

Answer:

  x-intercept: -14/9

  y-intercept: 7

Step-by-step explanation:

This is one of the easiest forms for finding intercepts. To find the x-intercept, set y=0 and divide both sides by the coefficient of x.

  -9x = 14 . . . . . set y=0

  x = -14/9 . . . . divide by -9

__

To find the y-intercept, set x=0 and divide both sides by the coefficient of y.

  2y = 14 . . . . set x=0

  y = 7 . . . . . . divide by 2

The x-intercept is -14/9; the y-intercept is 7.

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