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Liula [17]
3 years ago
6

The length of a rectangle is five centimeters more than its width, w. If the perimeter of the rectangle is 26 centimeters, what

is the area of the rectangle, in square centimeters?
A.104
B.676
C.36
D.26
Mathematics
1 answer:
dem82 [27]3 years ago
7 0
L is 5 more than W
L=5+W
P=2(L+W)
P=26
26=2(L+W)
L=5+W
sub
26=2(5+W+W)
divide both sides by 2
13=5+W+W
13=5+2W
minus 5 both sides
8=2W
divide 2 both sides
4=W

L=5+W
L=5+4
L=9

L=9 cm
W=4 cm

area=LW
area=9*4
are=36 cm^2

C is answer
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I'm confused. Can someone help?
VARVARA [1.3K]

a.

The polynomial w^2+18w+84 cannot be factored

The perfect square trinomial is w^2+18w + 81

----------

The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.

w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9

================================================

b.

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The perfect square trinomial is y^2-10y + 25

---------

Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.

If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)

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Step-by-step explanation:

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