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stiks02 [169]
2 years ago
11

Evaluate the expression when a=14 and b=6 −8ab= ?

Mathematics
2 answers:
Allisa [31]2 years ago
4 0

Answer:

- 8ab \\  \\  - 8 \times 14 \times 6 \\  \\  =  - 672

Natalija [7]2 years ago
3 0

Answer:

\\   \tt- 8ab

\\   \tt =  - 8 \times 14 \times 6

\\   \tt=  - 672

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meriva
The volume of a cuboid is given by length × width × height

We have:

Volume = 7.6 ft³
Height = 3x - 1
Length = x + 5
Width = x

Substituting these into the formula, we have:

7.6 = (3x - 1) (x + 5) (x)
7.6 = [3x² + 15x - x - 5] (x)
7.6 = [3x² + 14x - 5](x)
7.6 = 3x³ + 14x² - 5x
0 = 3x³ + 14x² - 5x - 7.6

Drawing the graph is one way of finding the solution (refer to the graph below):

We have three solutions (where the curve crosses the x-axis):
x = -4.9
x = -0.6
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Putting these solutions back into the context, since we are looking for the value of x which is part of measurement of length, we cannot have negative value, so we will take the value of x = 0.8 ft

Converting  0.8 ft into inches = 0.8 × 12 inches = 9.6 inches

Answer: x = 9.6 inches

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3 years ago
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5 0
3 years ago
Prove that for all integers a and b, if a mod 7 = 5 and b mod 7 = 6 then ab mod 7 = 2.
sergiy2304 [10]
Hello :
if : a <span>≡ 5 ( mod 7) ....(1)
     b </span><span>≡ 6 ( mod 7) ...(2)
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3 years ago
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4 0
2 years ago
Find the common fraction equivalent to 0.12
jonny [76]
The answer is:  " \frac{4}{33} "  .
______________________________
Given:  0.1212121212..... repeating ;  write that value as a fraction;
______________________________________________________
In other words; we are given:  "0.1212121212..... repeating infinitely" ;  

→ that is to say; "0.12 ...  ;  {the "12" decimal portion repeats infinitely} ; 
_______________________________________________________
→ We write this value, as a fraction, as:  "12/99" ;
__________________________________________
→Explanation:
__________________________________________ 


Note:  "0.99999999...... repeating infinitely;  =  "1" .
_________________________________________
→Since:

Let us say that we have: 

"x = 0.999999 ; repeating infinitely;  

In order words, let us say we have: "x = 0.9.... ;  the "9" decimal repeats infinitely; 
_____________________________________________________
   Then "10x" ;  (that is: "10" multlipled by "x";  or "10*x" or "10x" );  is equal to:

"10" * (0.999999.....)  = 9.99999999...... (the "9" decimal repeats infinitely);

in other words:  10x = 9.99999999....

Divide each side by "10" ;

to get "x = 0.9999999....." ; the decimal "9" repeats indefinitely...." ;

But if you have:  "10x = 10" ;  divide each side of the equation by "10" ; 
   you get: "x = 1" . 
____________________
Also,  if "x = 0.9999...(repeating infinitely); 

then:  10x = 9.99999.
_______________________________________________
           10x  =  9.999999999999999......
       −     x  =  0.999999999999999.......
    _____________________________________
            9x  =  9.00000000000000000000.....

 →  9x = 9 ; 

Divide each side of the equation; to get; 

 9x /9 = 9/ 9 ;  to get:  x = 1 ; and we have: x = 0.9999.... ;  so
  x= 0.99999.... = 1 ; 
__________________________________________________
So, if the numbers "12" is repeating, we divie "12" by "99" ; 
  that is; we divide "12" by "two 9's" ;  since "12" is a "TWO-digit number"; a "two-digit number" is being repeated infinitely.
________________________________________
            So;  0.12121212.....(the "12" is the decimal that repeats infinitely);            
                   
=  12/99 ;  which can be simplified;

Divide each side (both the numerator AND the denominator); by "3" ;
_________________________________________
  " 12/99 "  =  "(12÷3) / (99÷3) = 4/33 " .
_________________________________________
The answer is:  \frac{4}{33}  .
_________________________________________
8 0
3 years ago
Read 2 more answers
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