Answer:
6.20%
Step-by-step explanation:
Missing question and graph attached.
Given: Total number of sample collected for female between age 20-29 is 548.
34 females that weighed over 250 pounds.
Now, finding percentage of females aged 20 to 29 weighed over 250 pounds.
Percent of Female over 250 pound aged 20-29= ![\frac{Number\ of \ females\ over\ 250\ pounds}{Total\ number\ of\ females\ aged 20-29} \times 100](https://tex.z-dn.net/?f=%5Cfrac%7BNumber%5C%20of%20%5C%20females%5C%20over%5C%20250%5C%20pounds%7D%7BTotal%5C%20number%5C%20of%5C%20females%5C%20aged%2020-29%7D%20%5Ctimes%20100)
⇒Percent of Female over 250 pound aged 20-29= ![\frac{34}{548} \times 100](https://tex.z-dn.net/?f=%5Cfrac%7B34%7D%7B548%7D%20%5Ctimes%20100)
⇒ Percent of Female over 250 pound aged 20-29= ![0.0620437\times 100](https://tex.z-dn.net/?f=0.0620437%5Ctimes%20100)
∴ Percent of Female over 250 pound aged 20-29= ![6.20437 \approx 6.20\%](https://tex.z-dn.net/?f=6.20437%20%5Capprox%206.20%5C%25)
Hence, 6.20% of females aged 20 to 29 weighed over 250 pounds.
Answer:
tan theta = 2 sqrt(5) /15
Step-by-step explanation:
sin theta = opp / hypotenuse
sin theta = 2/7
We can use the Pythagorean theorem to find the length of the adjacent side
a^2 + b^2 = c^2
2^2 +adj^2 = 7^2
4 + adj^2 = 49
adj ^2 = 49-4
adj^2 = 45
Taking the square root of each side
adj = sqrt(45) = sqrt(9*5) =sqrt(9) sqrt(5) = 3 sqrt(5)
The tan theta = opp/ adj
tan theta = 2 / 3 sqrt(5)
Multiply by sqrt(5) / sqrt(5)
= 2 sqrt(5) / 3 *5
= 2 sqrt(5) /15
1.7 is the answer, first you would add up all of you numbers and then divide by 7
The graph is down on left side, up on right side.
Explanation:
The end behavior of the graph of a polynomial is determined by the its degree and the sign of the leading coefficient. For the even degrees the graph is either up or down on both ends i.e: the graph has the same direction on both ends . For the odd degrees the graph goes opposite directions. If the leading coefficient is positive the graph of even degree polynomials is up on both end and for the negative graph will be down on both ends. For the odd degree functions with positive leading coefficient the graph will be down on left, up on right but for negative will be up on left down on right.
Answer:
C
Step-by-step explanation:
I’m rusty with my math, so I’m not 100% sure this is correct. My best attempt.
(1,-5) & (3,-17)
1=1x, -5=1y, 3=2x, -17=2y
Formula is y2-y1/x2-x1
-17 - -5 = -12
3 - 1 =2
So -12/2 = -6
Formula for the line is
y-y1 = m (x-x1)
In this equation m=-6
Y - -5 = -6 ( x - 1 )