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vazorg [7]
3 years ago
9

How do I check 102÷17=6 without multiplying

Mathematics
1 answer:
insens350 [35]3 years ago
3 0
You could add 6 togetber 17 times? Sorry for the stupid answer I couldn't think of anything else I searched it up and I couldn't find anything at all
You might be interested in
Suppose y varies directly with x. if y=-3 when x=5 find y when x=-1
Scrat [10]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x

&&  y={{ k }}x
\end{array}
\\ \quad \\
\textit{we know that, when}
\begin{cases}
y=-3\\
x=5
\end{cases}\implies y=kx\implies (-3)=k(5)

solve for "k", to find the "constant of variation",
then plug it back in the y = kx, to get the equation
now
what's is y when x = -1?
well, just plug that in the equation with the found "k" value,
to get "y" :)
3 0
3 years ago
Read 2 more answers
HELP ASAP PLSSSSSSSSSSSS
ludmilkaskok [199]

Answer:

f = .39

Step-by-step explanation:

d (v) = 2.15 v^2 / (64.4 f)

v = 40

d = 138

substitute these in

138 = 2.15 (40)^2 / (64.4 *f)

simplify

138 = 2.15 (*1600) / (64.4 *f)

138 = 3440 / (64.4 *f)

multiply each side by 64.4f

138 * 64.4 f = 3440

8887.2 f = 3440

divide by 8887.2

8887.2 f /8887.2= 3440/8887.2

f=.38707

to the nearest hundredth

f = .39

8 0
3 years ago
Read 2 more answers
A line passes through the point (–6, –3) and has a slope of 2/3 . Which point is on the same line?
navik [9.2K]

Answer:

The point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

Step-by-step explanation:

We know that the slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given

  • The point (-6, -3)
  • The slope m = 2/3

Using the point-slope form

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

  • m = 2/3
  • (x₁, y₁) = (-6, -3)

substituting the values m = 2/3 and the point (-6, -3)  in the point-slope form

y-y_1=m\left(x-x_1\right)

y-\left(-3\right)=\frac{2}{3}\left(x-\left(-6\right)\right)

y+3=\frac{2}{3}\left(x+6\right)

Subtract 3 from both sides

y+3-3=\frac{2}{3}\left(x+6\right)-3

y=\frac{2}{3}x+4-3

y=\frac{2}{3}x+1

comparing with the slope-intercept form y=mx+b

Here the slope = m = 2/3

Y-intercept b = 1

We know that the value of y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

Given the line

y=\frac{2}{3}x+1

at x = 0, y = 1

Thus, the point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

5 0
3 years ago
What is the slope of the line that passes through the points (- 2, 2 ) and ( 8, -1 )
ELEN [110]

Answer: slope is -3/10

Step-by-step explanation:

3 0
3 years ago
Helpp me i need to get a 67 as my grade because i dont understand
Talja [164]

Answer:

6.5 minutes

Step-by-step explanation:

Divide T (total number of minutes) by M (total number of miles)

8 0
3 years ago
Read 2 more answers
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