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kvv77 [185]
3 years ago
7

What is the value of the expression below? |3| + |-3| + |-1|

Mathematics
1 answer:
never [62]3 years ago
3 0

Answer:

7

Step-by-step explanation:

After a number is taken out of the absolute value sign, it becomes positive. Therefore, |3| = 3, |-3| = 3, and |-1| = 1. Adding these up, we get 3 + 3 + 1 = 7

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7k÷3=21. What is the value of k?
viva [34]
7k/3 = 21
x 3       x3
7k = 63
/7      /7
k = 9
(7(9)/3 = 21    =    63/3 = 21    =    21 = 21)
5 0
3 years ago
Read 2 more answers
What is the<br> area of the rhombus?
cluponka [151]

Answer:

Area=36

Step-by-step explanation:

Area of rhombus: diagonal 1 x diagonal 2 divided by 2.

To find the area of a rhombus, you need to find the length of both diagonals(which is the distance between 2 points across from each other).

First, find the distance between -8 and 4 which is 12.

Next, find the distance between -1 and -7 which is 6.

12 x 6 =72

72/2=36

4 0
3 years ago
calcula la cantidad de liquido que se perdio en 20 dias de un contenedor que pierde 125 ml de agua al dia producto de la avapora
nikitadnepr [17]

Answer:

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4 0
4 years ago
A system of equations is graphed on the coordinate plane. y = -6x - 3, y = -x + 2, what is the solution of equations?
UkoKoshka [18]

(x, y ) → (- 1, 3 )

The solution to the system of equations is the point of intersection of the 2 lines

From the graph, that is (x, y ) → ( - 1, 3 )

We can confirm by solving algebraically

Since both equations express y in terms of x we can equate the right sides

- x + 2 = - 6x - 3 ( add 6x to both sides )

5x + 2 = - 3 ( subtract 2 from both sides )

5x = - 5 ( divide both sides by 5 )

x = - 1

substitute x = - 1 into either of the 2 equations for y-coordinate

y = - x + 2 = 1 + 2 = 3

solution is (x, y ) → (- 1, 3 )


8 0
3 years ago
Solve 5^3x+1 = 4^x-5 for x
tensa zangetsu [6.8K]

For the equation 5^{3x+1}=4^{x-5} take the \log from both sides:

\log 5^{3x+1}=\log 4^{x-5},\\ \\(3x+1)\log 5=(x-5)\log 4.

Find x:

3x\log 5+\log 5=x\log 4-5\log 4,\\ \\3x\log 5-x\log 4=-5\log 4-\log 5,\\ \\x(3\log 5-\log 4)=-5\log 4-\log 5,\\ \\x=\dfrac{-5\log 4-\log 5}{3\log 5-\log 4}=\dfrac{5\log 4+\log 5}{\log 4-3\log 5}.

Answer: correct choice is D

7 0
3 years ago
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