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pshichka [43]
3 years ago
15

IS MITOSIS CELL REPLICATION?

Mathematics
1 answer:
Svetlanka [38]3 years ago
3 0
It replicates the chromosomes
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3(-4n - 9) = 21 plc solve ​
erma4kov [3.2K]
<h3>Answer:</h3>

\huge{\boxed{n=-4}}

<h3>Explanation:</h3>

\begin{array}{cc}\begin{flushright}\text{Divide both sides of the equation by 3.}\end{flushright}&\begin{flushleft}-4n-9=7\end{flushleft}\\\begin{flushright}\text{Add 9 on both sides.}\end{flushright}&\begin{flushleft}-4n=16\end{flushleft}\\\begin{flushright}\text{Divide both sides by -4.}\end{flushrigh}&n=-4\end{array}

7 0
4 years ago
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....................
antiseptic1488 [7]

The answer is (A), or 8.

6 0
3 years ago
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In what rate of interest Rs 4000 amount to Rs 6000 in 2year​
PIT_PIT [208]

Principal = Rs 4000

Amount = Rs 6000

Time = 2 years

Rate = ?

Amount = principal + simple interest

Rs 6000 = Rs 4000 + simple interest

simple interest = Rs 6000 - Rs 4000 = Rs 2000

Simple interest = P*R*T/100

Rs 2000 = Rs 4000* R*2/100

R = 100/4 = 25%

8 0
3 years ago
Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
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Simply the following question in the photo
grin007 [14]

Answer:

Step-by-step explanation:

7 0
3 years ago
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