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Free_Kalibri [48]
2 years ago
14

Points j and k lie in plane h. how many lines can be drawn through points j and k? 0 1 2 3

Mathematics
1 answer:
UkoKoshka [18]2 years ago
4 0

Answer:

3

Step-by-step explanation:

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What is the equation of a circle with center (1, -4) and radius 2?
kvv77 [185]

Answer:

(x-1)^2 + (y+4)^2 = 4

Step-by-step explanation:

The equation for a circle is given by

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

(x-1)^2 + (y- -4)^2 = 2^2

(x-1)^2 + (y+4)^2 = 4

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2 years ago
12.3 + 17.8 - ( 3.3 x 2 )​
beks73 [17]
The answer to this problem is 23.5 . You are going to start by multiplying whats inside the paranthesis’s and then you’re going to calulate the sum and then difference and you should be left with 23.5
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3 years ago
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how will I put this in an equation a giraffe is 4 tines as tall as a gorilla the gorilla is 6 feet tall
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Answer:

WHY IS IT SO TALL

Step-by-step explanation:

WHY WHY WHY

7 0
2 years ago
Y = x + 4 <br> 2x - 3y = -13
pashok25 [27]

Answer:

(1,5)

Step-by-step explanation:

2x-3(x+4)=-13        y=1+4

2x-3x-12=-13          y=5

-x-12=-13

+12

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x=1

6 0
2 years ago
The coordinates of the image of line segment RT are R'(-2,-4) and T'(4.4). The image was produced by a dilation with a scale fac
Daniel [21]

Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:

For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:

R = 12R'

R = 12(-2, -4)

R = (-24, -48)

For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:

T = 12T'

T = 12(4, 4)

T = (48, 48)

Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)

6 0
1 year ago
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