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DENIUS [597]
3 years ago
6

TCP and the User Datagram Protocol (UDP) provide _________ between processes on any two of those hosts. A. address translation B

. reliable transport C. data transport D. performance enhancements
Computers and Technology
1 answer:
Fynjy0 [20]3 years ago
6 0

TCP is known to be a type of a connection-oriented protocol, while UDP is a connectionless protocol. TCP and UDP provide data transport between hosts.

  • TCP and UDP are known for their speed, as TCP is slower and can retransmit lost data packets than UDP. UDP is said to be faster, simpler, and efficient protocol.

Data transport is simply known to be an the energy problem. It is the amount of energy needed to transport a bit from the closest neighbor.

Data Transport Service gives  a reliable connection for moving large amounts of data at very fast speeds.

Learn more from

brainly.com/question/17695822

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What tool checks the spelling of each word against the programs internal dictonary?
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How does block chain support data privacy?
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2 years ago
Draw an FA over {0, 1}which represent binaries of Integers only divisible by 3. Allleading 0’s are permissible. [10]
suter [353]

Answer:

As we need to design the FA for the numbers divisible by 3, so we have to take the states as the remainders when we divide the numbers by 3.

Any number when divided by 3, gives remainder either 0 or 1 or 2. And the number gives remainder 0 is divisible by 3.

Let’s take

  • state 0 for remainder 0.
  • state 1 for remainder 1.
  • state 2 for remainder 2.

So now lets count from 0:

Binary 0 = decimal 0 %3 = 0, so goes to state 0.

Binary 1 =decimal 1 %3 = 1, goes to state 1.

Binary 10 = decimal 2 %3 =2, goes to state 2.

Bianary 11 = decimal 3 %3 =0, goes to state 0.

Bianary 100 = decimal 4 %3 =1, goes to state 1.

Bianary 101 = decimal 5 %3 =2, goes to state 2.

And so on.  

So here the state 0 will be the start state and also the final state.

Explanation:

So the FA is {{0,1,2}, {0,1}, δ, 0, {0}}

where δ(0, 0) = 0

           δ(0, 1) = 1

           δ(1, 0) = 2

           δ(1, 1) = 0

           δ(2, 0) = 1

           δ(2, 1) = 2

6 0
3 years ago
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