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3 years ago

I'm so confused plz help me

Mathematics

1 answer:

Alinara [238K]3 years ago

8 0

What one do you need help with?

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Match the graph of the equation: y=−6x2−12x−7

Vsevolod [243]

Answer:

Step-by-step explanation:

What graph

8 0

3 years ago

For this, find the value of X for this parallelogram!! Thank you :)

True [87]

Answer:

$\huge\boxed{\sf x = 12 }$

Step-by-step explanation:

Opposite sides and angles of a parallelogram are equal.

So,

3x - 1 = 35

Add 1 to both sides

3x = 35 + 1

3x = 36

Divide 3 to both sides

x = 36 / 3

x = 12

$\rule[225]{225}{2}$

Hope this helped!

7 0

3 years ago

The following triangle is equilateral triangle. Solve for the<br> unknown variable.<br> у<br> 17

Yuri [45]

Answer:

The following triangle is equilateral triangle. Solve for the

unknown variable. y=17 is the answer

7 0

3 years ago

What is 2 3/4 + -2 1/2

zimovet [89]

Answer:

1/4 or 0.25

Step-by-step explanation:

I did this on a graphic calculator so i can't really explain, but I hope this helps! :)

3 0

3 years ago

Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract

anyanavicka [17]

Answer:

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8$

Step-by-step explanation:

The sum you are trying to understand is this.

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}$

Remember that in general when you have a geometric series

$\sum\limits_{n = 0}^{\infty} a*r^n$ you have that

$\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}$ and that equality is true as long as $|r| < 1$ .

Therefore here we have

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n$ and $\big|\frac{-1}{15} \big| = \frac{1}{15} < 1$

Therefore we can use the formula and

$\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n = \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16 = 15/8$

5 0

3 years ago