Answer:
The width of the rectangular lid is 15 cm.
Step-by-step explanation:1. Let's review the information given to us to answer the question correctly:
Length of the ribbon used by Jun = 56 cmLength of the rectangular lid = 13 cm
2. What is the width of the lid? The ribbon used by Jun is equivalent to the perimeter of the rectangular lid, therefore:Perimeter = 2 * Length + 2 * WidthReplacing with the values we have:56 = 2 * 13 + 2 * Width56 = 26 + 2Width2Width = 56 - 262Width = 30Width = 30/2Width = 15
Since y represents miles and x represents weeks, it would be y=300x
ANSWER
The greatest common factor is
![{x}^{2} y](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20y)
EXPLANATION
We want to find the greatest common factor of
![9 {x}^{2} y](https://tex.z-dn.net/?f=9%20%7Bx%7D%5E%7B2%7D%20y)
and
![5 {x}^{4} {y}^{2}](https://tex.z-dn.net/?f=5%20%7Bx%7D%5E%7B4%7D%20%20%7By%7D%5E%7B2%7D%20)
The prime factorizations are;
![9 {x}^{2} y = {3}^{2} \times {x}^{2} \times y](https://tex.z-dn.net/?f=9%20%7Bx%7D%5E%7B2%7D%20y%20%3D%20%20%7B3%7D%5E%7B2%7D%20%20%5Ctimes%20%20%7Bx%7D%5E%7B2%7D%20%20%5Ctimes%20y)
and
![5 {x}^{4} {y}^{2} = 5 \times {x}^{4} \times {y}^{2}](https://tex.z-dn.net/?f=5%20%7Bx%7D%5E%7B4%7D%20%20%7By%7D%5E%7B2%7D%20%20%3D%205%20%5Ctimes%20%20%7Bx%7D%5E%7B4%7D%20%20%5Ctimes%20%20%7By%7D%5E%7B2%7D%20)
The product of the least powers of the common factors is the greatest common factor.
Answer:
x = 50.9
Step-by-step explanation:
35.6 = √(15.3²) + √(x²)
35.6 = 15.3 + x
x = 35.6 + 15.3
x = 50.9