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andrew-mc [135]
3 years ago
10

HELP PLEASE.. ............I'm sooooooooooooo bour.....?......​

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0
How about this one? Have a nice day.

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Delicious77 [7]

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i think it might be C

Step-by-step explanation:

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It would be amazing if you can help me with this !
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Step-by-step explanation:

Blank 1 = " x "

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A notebook costs £1.50, a pen costs 38p , a pencil costs 24p and a sharpener costs 83p.
Alex_Xolod [135]

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3

Step-by-step explanation:

(2 x 0.38) + (5 x 0.24) + (2 x 0.83) = £3.62

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What is 8/11 divided by 6/7
Radda [10]
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Obtain or compute the following quantities.
iVinArrow [24]

Answer:

a) F_{0.05,4,7}=0.16

b) F_{0.05,7,4}=0.24

c) F_{0.95,4,7}=4.12

d) F_{0.95,7,4}=6.09

e) F_{0.99,8,12}=4.50

f) F_{0.01,8,12}=0.18

g) P(F_{5,4} \leq 6.26)=0.95

h) P(0.177 \leq F_{10,5} \leq 4.74)=0.94

Step-by-step explanation:

(a) F0.05, 4, 7 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,4,7)". And we got:

F_{0.05,4,7}=0.16

(b) F0.05, 7, 4 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,7,4)". And we got:

F_{0.05,7,4}=0.24

(c) F0.95, 4, 7 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,4,7)". And we got:

F_{0.95,4,7}=4.12

(d) F0.95, 7, 4 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,7,4)". And we got:

F_{0.95,7,4}=6.09

(e) the 99th percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to two decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.99 of the area on the left tail. And we can use the following excel code: "=F.INV(0.99,8,12)". And we got:

F_{0.99,8,12}=4.50

(f) the 1st percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to three decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.01 of the area on the left tail. And we can use the following excel code: "=F.INV(0.01,8,12)". And we got:

F_{0.01,8,12}=0.18

(g) P(F ≤ 6.26) for v1 = 5, v2 = 4 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 5 degrees on the numerator and 4 on the denominator would be less or equal than 6.26. We can use the following excel code: "=F.DIST(6.26,5,4,TRUE)". And we got

P(F_{5,4} \leq 6.26)=0.95

(h) P(0.177 ≤ F ≤ 4.74) for v1 = 10, v2 = 5 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 10 degrees on the numerator and 5 on the denominator would be between 0.177 and 4.74. We can use the following excel code: "=F.DIST(4.74,10,5,TRUE)-F.DIST(0.177,10,5,TRUE)". And we got

P(0.177 \leq F_{10,5} \leq 4.74)=0.94

3 0
3 years ago
Read 2 more answers
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