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goldenfox [79]
3 years ago
9

. A National Institute of Health survey of 40467 U.S adults found that 3156 of them experienced at least one major depressive ep

isode in the previous year. Make a 95% confidence interval for the proportion of all U.S. adults who experienced depression in that year. (Source: https://www.nimh.nih.gov/health/statistics/major-depression)
Mathematics
1 answer:
mestny [16]3 years ago
5 0

Using the confidence interval for sample proportion formula, the C.I is (0.075; 0.081)

<u>Using</u><u> </u><u>the</u><u> </u><u>relation</u><u> </u><u>:</u>

<u>p ± z_{crit} \sqrt{ \frac{p(1 - p)}{n} }</u>

  • Sample size, n = 40467

  • Sample proportion, p = 3156/40467 = 0.078

  • Zcrit at 95% = 1.96

  • Margin of Error = 1.96 \sqrt{ \frac{0.078(0.922)}{40467} }

  • Margin of Error = 0.0026128

Lower boundary = 0.078 - 0.0026128 = 0.075

Upper boundary = 0.078 + 0.0026128 = 0.081

Hence, the confidence interval is (0.075; 0.081)

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Step-by-step explanation:

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