Question

The input nums is supposed to be an array of unique integers ranging from 1 to nums.length (inclusive). However, there is a mistake: one of the numbers in the array is duplicated, which means another number is missing. Find and return the sum of the duplicated number and the missing number. Example: in the array [4, 3, 3, 1], 3 is present twice and 2 is missing, so 3 2

Answer 1

The program is an illustration of loops.

Loops are used to perform repetitive and iterative operations.

The program in Python where comments are used to explain each line is as follows:

#This intializes the list

nums = [5,4,4,2,1]

#This gets the length of the list

size = len(nums)

#This iterates through the list

for i in range(size):

   #The following if condition determines the repeating number

   if nums[abs(nums[i])-1] > 0:

       nums[abs(nums[i])-1] = -nums[abs(nums[i])-1]

   else:

       repeating = abs(nums[i])

   #The following if condition determines the missing number

   if nums[i]>0:

       missing = i + 1

   

#This calculates and prints the sum of the missing and the repeating numbers

print(repeating+missing)

Read more about similar programs at:

brainly.com/question/13549861