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kumpel [21]
3 years ago
5

If 45.0 liters of oxygen is measured at 24.0C, what would be its volume at standard temperature?

Chemistry
1 answer:
nika2105 [10]3 years ago
6 0

The volume of the oxygen gas at standard temperature  is 41.36 liters.

The given parameters;

  • <em>initial volume of oxygen, V₁ = 45 L</em>
  • <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
  • <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>

<em />

The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;

\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 T_2}{T_1} \\\\V_2 = \frac{45 \times 273}{297} \\\\V_2 = 41.36 \ L

Thus, the volume of the oxygen gas at standard temperature  is 41.36 L.

Learn more here:brainly.com/question/16927784

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(Please explain the answer. Thank you!)
Dominik [7]

Sample cost = $15.796

<h3>Further explanation</h3>

Given

Mass = 2 g

Density = 0.718 g/ml

Cost =  $5.67 per mL

Required

Cost

Solution

The density : the ratio of mass and volume

Can be formulated :

Density (ρ) = m : V

The volume of the liquid :

V = m : ρ

V = 2 g : 0.718 g/ml

V = 2.786 ml

Sample cost :

= 2.786 ml x $5.67/ml

= $15.796

7 0
3 years ago
Compounds both and mixtures
zavuch27 [327]
Compounds=Chemically combined, fixed proportions,and components change properties.
Both= Made of elements, and 2 or more components.
Mixtures=Physically combined, variable proportions, and components retain properties.
6 0
4 years ago
_________ are elements of the same element that have a different _______________ due to a different number of _____________.
Andreas93 [3]

Answer: Isotopes

Explanation:

The atoms of a chemical element can exist in different types. These are called isotopes. They have the same number of protons (and electrons), but different numbers of neutrons. Different isotopes of the same element have different masses.

Hope this helps!

4 0
4 years ago
Whats the melting point of water
Harrizon [31]
The answer is 0°C
step by step explanation:
6 0
4 years ago
Read 2 more answers
The partial pressures of CH4, N2, and O2 in a sample of gas were found to be 143 mmHg, 469 mmHg, and 563 mmHg, respectively. Cal
wolverine [178]

<u>Answer:</u> The mole fraction of oxygen gas is 0.479

<u>Explanation:</u>

We are given:

Partial pressure of methane = 143 mmHg

Partial pressure of nitrogen gas = 469 mmHg

Partial pressure of oxygen gas = 563 mmHg

Total pressure = (143 + 469 + 563) = 1175 mmHg

To calculate the mole fraction of oxygen gas, we use the equation given by Raoult's law, which is:

p_{O_2}=p_T\times \chi_{O_2}

where,

p_{O_2} = partial pressure of oxygen gas = 563 mmHg

p_T = total pressure = 1175 mmHg

\chi_{O_2} = mole fraction of oxygen gas = ?

Putting values in above equation, we get:

563mmHg=1175mmHg\times \chi_{O_2}\\\\\chi_{O_2}=\frac{563}{1175}=0.479

Hence, the mole fraction of oxygen gas is 0.479

7 0
3 years ago
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