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alex41 [277]
3 years ago
14

Use the Mean Value Theorem to establish the fact that, for x>0,ex>1+x . (DO NOT use any other method).

Mathematics
1 answer:
valkas [14]3 years ago
5 0

e^{x} > 1 + x when e^{c} is removed from the expression derived by the mean value theorem.

Let be f(x) = e^{x}, for x > 0, according to the mean value theorem, also known as Rolle theorem, there is a value c\in (0, +\infty) so that:

f'(c) = \frac{f(x)-f(0)}{x-0} (1)

Where:

f'(c) - First derivative evaluated at c.

f(0) - Function evaluated at zero.

Then, we simplify the expression below:

x\cdot e^{c} = e^{x}-1

e^{x} = 1 + x\cdot e^{c}

Please that 1 + x is equalized to e^{x} because of e^{c}. If we eliminate e^{c}, then we find that e^{x} > 1 + x.

We kindly invite to check this question on mean value theorem: brainly.com/question/3957181

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Answer:

Step-by-step explanation:

The given equations are:

-9.5x – 2.5y = –4.3                    (1)

and 7x + 2.5y = 0.8                  (2)

Adding equation (1) and (2) together, we get

-9.5x-2.5y+7x+2.5y=-4.3+0.8

⇒-2.5x=-3.5

⇒x=1.4

Now, substitute the value of x=1.4 in equation (1),

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⇒-13.3-2.5y=-4.3

⇒-13.3+4.3=2.5y

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3 years ago
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Answer:

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Step-by-step explanation:

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